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我知道這可能已被問到,但我無法獲得具體答案。我有一個JSON字符串:從JSON字符串中提取單個元素
GraphObject{graphObjectClass=GraphPlace, state={"id":"268367713308665","category":"School","location":{"state":"","zip":"","longitude":32.631482614136,"latitude":0.24519375867929,"country":"Uganda","city":"Kampala","street":"PO BOX 28493"},"category_list":[{"id":"365182493518892","name":"School"}],"name":"Little Wonders Montessori"}}
GraphObject{graphObjectClass=GraphPlace, state={"id":"142442605900768","category":"Education","location":{"state":"","zip":"","longitude":32.606752647018,"latitude":0.28746491511647,"country":"Uganda","city":"Kampala","street":"Heritage\/ Kiwafu Stage, Wheeling Zone, Gaba Road, Kansanga"},"category_list":[{"id":"151676848220295","name":"Education"}],"name":"Wisdomgate Pre-School, Kansanga."}}
其中我從Facebook獲得,當我查詢附近的位置,我想提取緯度,經度,類別和名稱。 這就是我試圖
public void onCompleted(List<GraphPlace> places, Response response) {
//Toast.makeText(getActivity(), (CharSequence) places.listIterator(), Toast.LENGTH_LONG).show();
ListIterator<GraphPlace> x = places.listIterator();
while(x.hasNext()){
String f = x.next().toString();
Toast.makeText(getActivity(), f, Toast.LENGTH_LONG).show();
mytext.setText(f);
try {
JSONObject json = new JSONObject(f);
JSONArray array = json.getJSONArray("GraphPlace");
Toast.makeText(getActivity(), array.length(), Toast.LENGTH_LONG).show();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
});
request.executeAsync();
不過,我似乎無法得到一個入口點,並且也不管我嘗試,我不能得到任何感謝提前的幫助。
感謝布萊恩,所以,我想知道,如果我的字符串以GraphObject開始{graphObjectClass = GraphPlace,state = ...,我必須先格式化它,並刪除我不想要的第一部分? –
我不太確定。我還沒有見過這樣的迴應。 JSON不使用'='符號。檢查FB文檔並查看是否有與刪除所需代碼相關的方法。 – BlackHatSamurai