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我有這段代碼,它檢查一些id並啓用其他代碼,javascript很清楚它做了什麼,但是因爲它對應於某些特定的id範圍,所以我不能做一看,直到它完成,但我正在尋找一種方法來做到這一點動態和保存40行代碼(或更多),因爲它不是最好的方式。Javascript:製作一個靜態代碼,動態 - 輸入列表
function loopGroup1() {
var a = 0;
do {
$$('.selectedAuthorities-3_' + a).each(function(chk1) {
// watch for clicks
chk1.observe('click', function(evt) {
dynamicCheckbox1();
});
dynamicCheckbox1();
});
a++;
} while (a < 4);
}
function dynamicCheckbox1() {
// count how many of group_first are checked,
// doEnable true if any are checked
var doEnable = ($$('.selectedAuthorities-3_0:checked').length > 0) ? true
: false;
var doEnable1 = ($$('.selectedAuthorities-3_1:checked').length > 0) ? true
: false;
var doEnable2 = ($$('.selectedAuthorities-3_2:checked').length > 0) ? true
: false;
// for each in group_second, enable the checkbox, and
// remove the cssDisabled class from the parent label
var i = 0;
do {
$$('.selectedAuthorities-4_' + i).each(function(item) {
if (doEnable || doEnable1 || doEnable2) {
item.enable().up('li').removeClassName('cssDisabled');
} else {
item.disable().up('li').addClassName('cssDisabled');
}
});
i++;
} while (i < 4);
};
/*
*
* Loop Group 2
*
*
*/
function loopGroup2() {
var a = 0;
do {
$$('.selectedAuthorities-5_' + a).each(function(chk1) {
// watch for clicks
chk1.observe('click', function(evt) {
dynamicCheckbox2();
});
dynamicCheckbox2();
});
a++;
} while (a < 4);
}
function dynamicCheckbox2() {
// count how many of group_first are checked,
// doEnable true if any are checked
var doEnable3 = ($$('.selectedAuthorities-5_0:checked').length > 0) ? true
: false;
// for each in group_second, enable the checkbox, and
// remove the cssDisabled class from the parent label
var i = 0;
do {
$$('.selectedAuthorities-6_' + i).each(function(item) {
if (doEnable3) {
item.enable().up('li').removeClassName('cssDisabled');
} else {
item.disable().up('li').addClassName('cssDisabled');
}
});
i++;
} while (i < 4);
};
/*
*
* Loop Group 3
*
*
*/
function loopGroup3() {
var a = 0;
do {
$$('.selectedAuthorities-6_' + a).each(function(chk1) {
// watch for clicks
chk1.observe('click', function(evt) {
dynamicCheckbox3();
});
dynamicCheckbox3();
});
a++;
} while (a < 4);
}
function dynamicCheckbox3() {
// count how many of group_first are checked,
// doEnable true if any are checked
var doEnable4 = ($$('.selectedAuthorities-6_0:checked').length > 0) ? true
: false;
var doEnable5 = ($$('.selectedAuthorities-6_1:checked').length > 0) ? true
: false;
// for each in group_second, enable the checkbox, and
// remove the cssDisabled class from the parent label
var i = 0;
do {
$$('.selectedAuthorities-7_' + i).each(function(item) {
if (doEnable4 || doEnable5) {
item.enable().up('li').removeClassName('cssDisabled');
} else {
item.disable().up('li').addClassName('cssDisabled');
}
});
i++;
} while (i < 4);
};
/*
*
* Loop Group 4
*
*
*/
function loopGroup4() {
var a = 0;
do {
$$('.selectedAuthorities-9_' + a).each(function(chk1) {
// watch for clicks
chk1.observe('click', function(evt) {
dynamicCheckbox4();
});
dynamicCheckbox4();
});
a++;
} while (a < 4);
}
function dynamicCheckbox4() {
// count how many of group_first are checked,
// doEnable true if any are checked
var doEnable6 = ($$('.selectedAuthorities-9_0:checked').length > 0) ? true
: false;
var doEnable7 = ($$('.selectedAuthorities-9_1:checked').length > 0) ? true
: false;
// for each in group_second, enable the checkbox, and
// remove the cssDisabled class from the parent label
var i = 0;
do {
$$('.selectedAuthorities-10_' + i).each(function(item) {
if (doEnable6 || doEnable7) {
item.enable().up('li').removeClassName('cssDisabled');
} else {
item.disable().up('li').addClassName('cssDisabled');
}
});
i++;
} while (i < 4);
};
代碼中有很多不必要的重複,也許更具體的與你正在嘗試做什麼,即我想採用這個函數X,並允許它適用於任何一組複選框或東西。很難說出你在問什麼「我不能只看看它,直到它完成,但我正在尋找一種方法來做到這一點動態」 – 2010-05-14 23:10:23