c＃ - 計算 - RNG遊戲

Question

我正在製作一款足球遊戲。爲了獲得達陣，你必須獲得100碼。我有public static int yardsLeft = 100;。它經歷一個循環，獲得每個通過的許多碼。一旦yardsLeft = 0，它將退出。我試圖弄清楚如何讓最後獲得的場地（達陣）達到100碼。

我有這樣的：

if (Program.yardsLeft >= 80) 
{ 
    if (Program.chance >= 1 && Program.chance <= 5) 
     Program.gained = Program.r.Next(80, (100 + 1)); 

    else if (Program.chance >= 6 && Program.chance <= 12) 
     Program.gained = Program.r.Next(60, (79 + 1)); 

    else if (Program.chance >= 13 && Program.chance <= 24) 
     Program.gained = Program.r.Next(20, (59 + 1)); 

    else if (Program.chance >= 25 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, (19 + 1)); 
} 
else if (Program.yardsLeft <= 79 && Program.yardsLeft >= 60) 
{ 
    if (Program.chance >= 1 && Program.chance <= 10) 
     Program.gained = Program.r.Next(60, 80); 

    else if (Program.chance >= 11 && Program.chance <= 30) 
     Program.gained = Program.r.Next(20, 60); 

    else if (Program.chance >= 31 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, 20); 
} 
else if (Program.yardsLeft <= 59 && Program.yardsLeft >= 40) 
{ 
    if (Program.chance >= 1 && Program.chance <= 10) 
     Program.gained = Program.r.Next(40, 60); 

    else if (Program.chance >= 11 && Program.chance <= 30) 
     Program.gained = Program.r.Next(20, 40); 

    else if (Program.chance >= 31 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, 20); 
} 
else if (Program.yardsLeft <= 39 && Program.yardsLeft >= 20) 
{ 
    if (Program.chance >= 1 && Program.chance <= 10) 
     Program.gained = Program.r.Next(30, 40); 

    else if (Program.chance >= 11 && Program.chance <= 30) 
     Program.gained = Program.r.Next(10, 30); 

    else if (Program.chance >= 31 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, 10); 
} 
else if (Program.yardsLeft <= 19) 
{ 
    if (Program.chance >= 1 && Program.chance <= 10) 
     Program.gained = Program.r.Next(15, 20); 

    if (Program.chance >= 11 && Program.chance <= 30) 
     Program.gained = Program.r.Next(10, 15); 

    if (Program.chance >= 31 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, 10); 
} 

首先它會檢查yardsLeft超過80，如果是，它必須獲得這麼多碼（100）的機會，但如果第一次通過，它不會超過20碼（繼續下一個檢查else if (Program.yardsLeft <= 79 && Program.yardsLeft >= 60)它將會直接回到else if (Program.yardsLeft <= 79 && Program.yardsLeft >= 60)並再次添加一些導致達到100的東西，意味着在最後，結果將通過100。

示例

if (yardsLeft is 80 or more) 
    { 
     // generate number somewhere through 60-80 (not ever exceed 100) 
     // generate number somehwere between 20-60 (not ever exceeding 100 
     // generator number somewehere between 1-20 (not ever exceeding 100) 
    } 
    else if (yardsLeft is between 60-20) 
    { 
     // generate number somewhere through 40-60 (not ever exceed 100) 
     // generate number somehwere between 20-40 (not ever exceeding 100 
     // generator number somewehere between 1-20 (not ever exceeding 100) 
    } 

最終結果CAN NOT超過100.這就是我想說的。每次循環的時間，我希望它產生一些數字，在年底，將不會超過100

Answer 1

一個簡單的解決辦法是隻需將這個塊代碼後剩下：

Program.gained = Math.Min(Program.gained, Program.yardsLeft); 

這意味着，如果所獲得的碼比去0所需的碼數大，它將被設置爲左側的碼數。所以，當你以後（大概）由Program.gained遞減Program.yardsLeft，它不會小於0

---

基礎知識：Math.Min返回最小你給它的參數。此聲明將Program.gained設置爲基於較早代碼中給出的值的新值。這會將Program.gained的值「夾」到yardsLeft以下。這裏有一個簡單的用法：

int yardsYouCanRun = 112; 
int yardsYouTraveled = Math.Min(yardsYouCanRun, 100); 
// yardsYouTraveled is Math.Min(112, 100), which is 100. 

int yardsICanRun = 15; 
int yardsITraveled = Math.Min(yardsICanRun, 100); 
// yardsITraveled is Math.Min(15, 100), which is 15. 

這代表您追蹤你可以從零運行，但希望將其限制在100，因爲這是你所能運行的最大距離碼數的情況。兩者中的最小值是距離。正如你所看到的，你可以跑全程，但是我只能跑15碼，所以你得到了100碼的達陣，但我只能在15碼線。這是將「yardsXCanRun」的值「夾緊」在100碼以下。

這與前面的代碼行相同，但是您不需要運行100碼，您只能運行Program.yardsLeft。

Answer 2

我覺得你是想是這樣的：

if (Program.yardsLeft >= 80) 
    { 
     if (Program.chance >= 1 && Program.chance <= 5) 
      Program.gained = Program.r.Next(80, (100 + 1)); 

     else if (Program.chance >= 6 && Program.chance <= 12) 
      Program.gained = Program.r.Next(60, (79 + 1)); 

     else if (Program.chance >= 13 && Program.chance <= 24) 
      Program.gained = Program.r.Next(20, (59 + 1)); 

     else if (Program.chance >= 25 && Program.chance <= 100) 
      Program.gained = Program.r.Next(1, (19 + 1)); 
    } 
    else if (Program.yardsLeft <= 79 && Program.yardsLeft >= 60) 
    { 
     if (Program.chance >= 1 && Program.chance <= 10) 
      Program.gained = Program.r.Next(60, 80); 

     else if (Program.chance >= 11 && Program.chance <= 30) 
      Program.gained = Program.r.Next(20, 60); 

     else if (Program.chance >= 31 && Program.chance <= 100) 
      Program.gained = Program.r.Next(1, 20); 
    } 
    else if (Program.yardsLeft <= 59 && Program.yardsLeft >= 40) 
    { 
     if (Program.chance >= 1 && Program.chance <= 10) 
      Program.gained = Program.r.Next(40, 60); 

     else if (Program.chance >= 11 && Program.chance <= 30) 
      Program.gained = Program.r.Next(20, 40); 

     else if (Program.chance >= 31 && Program.chance <= 100) 
      Program.gained = Program.r.Next(1, 20); 
    } 
    else if (Program.yardsLeft <= 39 && Program.yardsLeft >= 20) 
    { 
     if (Program.chance >= 1 && Program.chance <= 10) 
      Program.gained = Program.r.Next(30, 40); 

     else if (Program.chance >= 11 && Program.chance <= 30) 
      Program.gained = Program.r.Next(10, 30); 

     else if (Program.chance >= 31 && Program.chance <= 100) 
      Program.gained = Program.r.Next(1, 10); 
    } 
    else if (Program.yardsLeft <= 19 && Program.yardsLeft !>= 100) 
    { 
     if (Program.chance >= 1 && Program.chance <= 10) 
     Program.gained = Program.r.Next(15, 20); 

    if (Program.chance >= 11 && Program.chance <= 30) 
     Program.gained = Program.r.Next(10, 15); 

    if (Program.chance >= 31 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, 10); 
    } 
    else 
    {return;}//return the value if over 100 

只要你沒有把一個參數檢查最後剩下的碼數是否超過100 elseif

另一種做你在這裏的方法是通過使用.yardsLeft使得隨機動態只允許你達到100，而不會更多。

if (Program.chance >= 31 && Program.chance <= 100) 
     Program.gained = Program.r.Next(1, program.yardsLeft);