命名路線及的link_to問題

Question

我有以下的路線設置：

map.people 'people(.:format)', :conditions => { :method => :get }, :controller=>"people", :action=>"index" 
map.connect 'people(.:format)', :conditions => { :method => :post }, :controller=>"people", :action=>"create" 
map.new_person 'people/new(.:format)', :conditions => { :method => :get }, :controller=>"people", :action=>"new" 
map.edit_person 'people/:shortname/edit(.:format)', :conditions => { :method => :get }, :controller => 'people', :action => 'edit' 
map.person 'people/:shortname(.:format)', :conditions => { :method => :get }, :controller=>"people", :action=>"show" 
map.connect 'people/:shortname(.:format)', :conditions => { :method => :put }, :controller=>"people", :action=>"update" 
map.connect 'people/:shortname(.:format)', :conditions => { :method => :delete }, :controller=>"people", :action=>"destroy" 

我想使用的link_to函數的視圖頁面像：

<%= link_to 'Show', person_path(person.shortname) %> 

這給了我這個錯誤，我不知道我做錯了：

person_url failed to generate from {:controller=>"people", :shortname=>"efleming", :action=>"show"}, expected: {:controller=>"people", :action=>"show"}, diff: {:shortname=>"efleming"} 

Answer 1

圍繞(:format)的括號正在拋棄您的路由。你需要這樣做在parens？如果刪除它們，並改變map.person線一樣，那麼你將被罰款：

map.person 'people/:shortname.:format', :conditions => { :method => :get }, :controller=>"people", :action=>"show" 

在這種情況下的link_to因爲你擁有它會正常工作。

Answer 2

我相信你的鏈接應該是這樣的：

<%= link_to 'Show', person_path(:shortname => person.shortname) %>