保存對象的變量解析它

Question

我有這樣的對象：

var eventsDates = new Array(
    "basket":"11-10-2012", 
    "soccer":"21-10-2012", 
    "soccer":"28-10-2012", 
    "baseball":"25-11-2012", 
    "baseball":"15-12-2012" 
); 

，我需要通過例如競爭只有足球不是儲蓄導致這樣

var eventsDates = new Array(
    "21-10-2012", 
    "28-10-2012" 
); 

任何建議

提取日期

Luca

Answer 1

請勿混用arrays和objects使用其中之一：

var eventDates = [ 
    "11-10-2012", 
    "21-10-2012", 
    "28-10-2012", 
    "25-11-2012", 
    "15-12-2012" 
]; 

OR

var eventDates = { 
    "basket":"11-10-2012", 
    "soccer":"21-10-2012", 
    "soccer":"28-10-2012", 
    "baseball":"25-11-2012", 
    "baseball":"15-12-2012" 
}; 

這就是說，你不能重複使用相同的密鑰（如baseball），所以最好的結構將是下列之一：

var eventDates = { 
    "basket": ["11-10-2012"], 
    "soccer": ["21-10-2012", "28-10-2012"] 
    "baseball": ["25-11-2012", "15-12-2012"] 
}; 

而像eventDates.baseball

$.each(eventDates.baseball, function (k, v) { 
    alert(v); 
}); 

訪問

你也可以做以下事情，但是你必須使用一個自定義的提取器， ld包括在你想要日期的任何時候遍歷整個數組，只有某個name。

var eventDates = [ 
    {"name": "basket", "date":"11-10-2012"}, 
    {"name":"soccer", "date":"21-10-2012"}, 
    {"name": "soccer", "date":"28-10-2012", 
    {"name": "baseball", "date":"25-11-2012"}, 
    {"name":"baseball", "date":"15-12-2012"} 
]; 

Answer 2

我會考慮這種任務的不同數據結構：

var eventDates = { 
    Soccer: [{ 
     date: ... 
    ]}, 
    Basket: [{ 
     date: ... 
    ]} 
}; 

然後你可以很容易地訪問f.e.所有足球日期：

for (var i = 0; i <= eventDates.Soccer.length; i++) { 
    // Do something with eventDates.Soccer[i] 
} 

Answer 3

var eventsDates = { 
    "basket":["11-10-2012"], 
    "soccer":["21-10-2012","28-10-2012"], 
    "baseball":["25-11-2012","15-12-2012"] 
    } 


var soccerDates = eventsDates.soccer; 

Answer 4

它看起來像你建議你有一個陣列內的一系列對象：

var events = [ 
    {"basket":"11-10-2012"}, 
    {"soccer":"21-10-2012"}, 
    {"soccer":"28-10-2012"}, 
    {"baseball":"25-11-2012"}, 
    {"baseball":"15-12-2012"} 
]; 

var count = events.length, dates = [], m; 

while (count--) 
    if (m = events[count]["soccer"]) 
     dates.push(m); 

console.log(dates); 

小提琴：http://jsfiddle.net/YX4Kq/