INNER JOIN別名sintax

Question

我有這個

選擇
p.id， p.name， p.code， clA.code爲claCode， sclA.code爲sclaCode， clB.code作爲clbCode， sclB.code爲sclbCode， clC.code爲clcCode， sclC.code作爲sclcCode

FROM 
      products p 
       INNER JOIN catleathers clA 
        ON p.catleather_id_a = clA.id 
       INNER JOIN subcatleathers sclA 
        ON p.subcatleather_id_a = sclA.id 
       INNER JOIN catleathers clB 
        ON p.catleather_id_b = clB.id 
       INNER JOIN subcatleathers sclB 
        ON p.subcatleather_id_b = sclB.id 
       INNER JOIN catleathers clC 
        ON p.catleather_id_c = clC.id 
       INNER JOIN subcatleathers sclC 
        ON p.subcatleather_id_c = sclC.id 

但我需要這樣的事

function getdatatableajaxcost() 
    { 

    $this->load->library('datatables'); 
    $this->datatables 

    ->select(" 



      products.id as productid, 
      products.code as code, 
      products.name as name, 

      clA.code as claCode, 
      sclA.code as sclaCode, 
      clB.code as clbCode, 
      sclB.code as sclbCode, 
      clC.code as clcCode, 
      sclC.code as sclcCode, 

      products.details", FALSE) 

      ->from('products') 
      ->join('catleathers clA', 'products.catleather_id_a = clA.id', 'INNER') 
      ->join('subcatleathers sclA', 'products.subcatleather_id_a = sclA.id', 'INNER') 
      ->join('catleathers clB', 'products.catleather_id_a = clB.id', 'INNER') 
      ->join('subcatleathers sclB', 'products.subcatleather_id_a = sclB.id', 'INNER') 
      ->join('catleathers clC', 'products.catleather_id_a = clC.id', 'INNER') 
      ->join('subcatleathers sclC', 'products.subcatleather_id_a = sclC.id', 'INNER') 
      ->group_by("products.id"); 

      $this->datatables->unset_column('productid'); 
      $this->datatables->unset_column('image'); 

      echo $this->datatables->generate(); 

請一定幫忙！

Answer 1

解決！ 謝謝大家！

->select(" 

      products.id as productid, 
      products.image as image, 
      products.code as code, 
      products.name as name, 
      categories.name as cname, 
      subcategories.name as subcategory, 
      products.cost, 
      products.price, 

      clA.code as claCode, 
      sclA.code as sclaCode, 
      clB.code as clbCode, 
      sclB.code as sclbCode, 
      clC.code as clcCode, 
      sclC.code as sclcCode, 

      catSoleA.code as catSoleACode, 
      subcatSoleA.code as subcatSoleACode, 

      catSoleB.code as catSoleBCode, 
      subcatSoleB.code as subcatSoleBCode, 

      catSoleC.code as catSoleCCode, 
      subcatSoleC.code as subcatSoleCCode, 

      products.details", FALSE) 

      ->from('products') 
      ->join('categories', 'products.category_id=categories.id', 'left') 
      ->join('subcategories', 'products.subcategory_id=subcategories.id', 'left') 

      ->join('catleathers clA', 'products.catleather_id_a = clA.id', 'INNER') 
      ->join('subcatleathers sclA', 'products.subcatleather_id_a = sclA.id', 'INNER') 

      ->join('catleathers clB', 'products.catleather_id_b = clB.id', 'INNER') 
      ->join('subcatleathers sclB', 'products.subcatleather_id_b = sclB.id', 'INNER') 

      ->join('catleathers clC', 'products.catleather_id_c = clC.id', 'INNER') 
      ->join('subcatleathers sclC', 'products.subcatleather_id_c = sclC.id', 'INNER') 

      ->join('catsoles catSoleA', 'products.catsole_id_a = catSoleA.id', 'INNER') 
      ->join('subcatsoles subcatSoleA', 'products.subcatsole_id_a = subcatSoleA.id', 'INNER') 

      ->join('catsoles catSoleB', 'products.catsole_id_b = catSoleB.id', 'INNER') 
      ->join('subcatsoles subcatSoleB', 'products.subcatsole_id_b = subcatSoleB.id', 'INNER') 

      ->join('catsoles catSoleC', 'products.catsole_id_c = catSoleC.id', 'INNER') 
      ->join('subcatsoles subcatSoleC', 'products.subcatsole_id_c = subcatSoleC.id', 'INNER') 


      ->group_by("products.id");