如何在Visual C++ 2010中設置簡單的LinkedList？

Question

我是Visual C++新手。我寫了我的班，但它有錯誤

錯誤1錯誤C3845：'CRegistration :: list1'：只有靜態數據成員可以在ref類或值類型內初始化c：\ users \ marco \ desktop \ cs351 \ hw3 \ project3 \ CRegistration.h 44 1項目3

我明白編譯器已經說過錯誤是什麼。但是，我不明白它的意思。以下是我的代碼

#pragma once 

using namespace System; 
using namespace System::ComponentModel; 
using namespace System::Collections; 
using namespace System::Windows::Forms; 
using namespace System::Data; 
using namespace System::Drawing; 
using namespace System::Collections; 
using namespace System::Collections::Generic; 


public ref class CRegistration 
{ 
public: 

    CRegistration(void){ 

     ClickBoxRecord = 0; 

     ClickBoxRecord = 0; 


    };//end constructor 

    void SetRadioRecord(int flag){ RadioRecordRecord = flag; } 

    void SetClickBoxRecord(int flag){ ClickBoxRecord = flag; } 

    int GetRadioRecordRecord(){return RadioRecordRecord} 

    int GetClickBoxRecord(){return ClickBoxRecord} 



protected: 

private: 

    int RadioRecordRecord; 

    int ClickBoxRecord; 

    LinkedList<int> list1 = gcnew LinkedList<int>(); 

    LinkedList<String^> ^list2 = gcnew LinkedList<String^>(); 

    LinkedList<String^> ^list3 = gcnew LinkedList<String^>(); 

    LinkedList<String^> ^list4 = gcnew LinkedList<String^>(); 

    LinkedList<String^> ^list5 = gcnew LinkedList<String^>(); 


};//end ref class 

Answer 1

您是要學習C++還是想學習CLI？

// native C++ 
#include <list> 
#include <string> 

std::list<int> list1; 
std::list<double> list2; 
std::list<std::string> list3; 
std::list<std::string> list4; 
std::list<std::string> list5; 

P.S.

問題是非靜態成員list1到list5的內聯初始化。在C++中，非靜態成員的初始化通常在初始化器列表或構造器的主體中完成。在C++中，我們通常儘可能地使用堆棧，只有在必須使用堆時，內存管理纔是重要的。

// C++/CLI 

// you can either make a list of each 
LinkedList<int> list1; // list of int 
LinkedList<double> list2; // list of double 
LinkedList<String> list3; // list of String 

// or make an object that has one of each 
public ref class AllThree { 
    public: 
     // members 
     String str; 
     double dbl; 
     int i; 
}; 

// and make a list of that object 
LinkedList<AllThree> list4; // list of AllThree