2012-08-04 37 views
2

所以通常我可以做類似訪問用戶管理器中的控制單元,如何在Symfony中使用FosUserBundle作爲服務訪問用戶管理器?

$this->get('fos_user.user_manager'); 

但是我已經需要訪問這一項服務。所以這是我做過什麼:

在我config.yml文件:

fos_user: 
    db_driver: orm 
    firewall_name: main 
    user_class: Main\UserBundle\Entity\User 



services: 
    userbundle_service: 
     class:  Main\UserBundle\Controller\UserBundleService 
     arguments: [@fos_user] 

在我UserBundleService.php「:

<?php 
namespace Main\UserBundle\Controller; 

use FOS\UserBundle\Entity\User; 
use Symfony\Component\Security\Core\SecurityContextInterface; 
use Symfony\Bridge\Monolog\Logger; 



class UserBundleService 
{ 

    protected $securityContext; 

    public function __construct(User $user) 
    { 
     $this->user = $user; 
    } 


    public function validateRequest(){  
    $userManager = $this->container->get('fos_user.user_manager'); 
    $this ->logger->warn("user is : ".$userManager); 
    exit; 

    } 

} 

我得到的錯誤是:

ServiceNotFoundException: The service "userbundle_service" has a dependency on a non-existent service "fos_user". 

所以接下來我要做的就是將fos_user作爲服務移動到我的config.yml中:

services: 
    userbundle_service: 
     class:  Main\UserBundle\Controller\UserBundleService 
     arguments: [@fos_user2] 

    fos_user2: 
     user_class: Main\UserBundle\Entity\User 

我得到的錯誤:

RuntimeException: The definition for "fos_user2" has no class. If you intend to inject this service dynamically at runtime, please mark it as synthetic=true. If this is an abstract definition solely used by child definitions, please add abstract=true, otherwise specify a class to get rid of this error. 
+5

ma nager被命名爲'fos_user.user_manager',所以你必須把整個兩個單詞放在你的參數中:''參數:[@ fos_user.user_manager]''userbundle_service'。 – Sgoettschkes 2012-08-04 17:55:23

回答

5

你必須注入服務正好與相同的名稱,你通常在你的控制器使用服務容器得到它:

services: 
    userbundle_service: 
     class:  Main\UserBundle\Controller\UserBundleService 
     arguments: [@fos_user.user_manager] 

你也可以在控制檯app/console container:debug中打電話,並檢查你有哪些容器

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