2017-01-31 134 views
0

好吧,所以我讓用戶登錄,然後「如果成功」我將他們重定向到index.php我想從數據庫中顯示一些信息。會話在PHP不工作

我的用戶已驗證,我可以登錄,但我認爲我在會話中遇到了問題。

當我在index.php頁面調用它時,用戶名會話不顯示任何信息。

我是新來的PHP和學習,因爲我去。我已經花了兩天時間瀏覽本網站,以查找我的問題的答案,但無法找到任何真正有用的東西。

下面是代碼

checklogin.php

<?php 

    session_start(); 
    ob_start(); 
    include_once 'config.php'; 

    // Connect to server and select databse. 
    try 
    { 
     $pdo_options[PDO::ATTR_ERRMODE] = PDO::ERRMODE_EXCEPTION; 
     $db = new PDO('mysql:host='.$host.';dbname='.$db_name.';charset=utf8', $username, $password); 
    } 
    catch(Exception $e) 
    { 
     die('Error : ' . $e->getMessage()); 
    } 

    // Define $myusername and $mypassword 
    $myusername = $_POST['myusername']; 
    $mypassword = $_POST['mypassword']; 

    // To protect MySQL injection 
    $myusername = stripslashes($myusername); 
    $mypassword = stripslashes($mypassword); 

    $stmt = $db->query("SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"); 

    // rowCount() is counting table row 
    $count = $stmt->rowCount(); 

    // If result matched $myusername and $mypassword, table row must be 1 row 
    if($count == 1){ 

     // Register $myusername, $mypassword and print "true" 
     echo "true"; 
     $_SESSION['username'] = 'myusername'; 
     $_SESSION['password'] = 'mypassword'; 

    } 
    else { 
     //return the error message 
     echo "<div class=\"alert alert-danger alert-dismissable\"><button type=\"button\" class=\"close\" data-dismiss=\"alert\" aria-hidden=\"true\">&times;</button>Wrong Username or Password</div>"; 
    } 

    ob_end_flush(); 
?> 

的index.php

<?php 
    session_start(); 

    if(!isset($_SESSION['username'])){ 
    header("location:main_login.php"); 
    } 
?> 
<!DOCTYPE html> 
<html lang="en"> 
<head> 
<meta charset="utf-8"> 
<title>Login</title> 
<meta name="viewport" content="width=device-width, initial-scale=1.0"> 
<!-- Bootstrap --> 
<link href="css/bootstrap.css" rel="stylesheet" media="screen"> 
<link href="css/main.css" rel="stylesheet" media="screen"> 
</head> 
<body> 
<div class="container"> 
    <div class="form-signin"> 
    <div class="alert alert-success">You have been <strong>successfully</strong> logged in <?php echo $_SESSION['username']; ?>.</div> 
    <a href="logout.php" class="btn btn-default btn-lg btn-block">Logout</a> </div> 
</div> 
<!-- /container --> 
</body> 
</html> 

我真的很感激任何幫助或鏈接文章,可以幫助。

由於

肖恩

+0

您的會話已啓用嗎?使用phpinfo()檢查; –

+0

嗨,這裏是我的phpinfo()必須說 - http://prntscr.com/e2n4bn –

+0

所以是的,我會說這是啓用 –

回答

0

只要改變$ _SESSION [ '用戶名'] = '名爲myUsername';到$ _SESSION ['username'] = $ myusername;