ROW_NUMBER根據條件跳過行

Question

我有一個日曆表，每個日期都有一個鍵（整數）列。有效的商業日期被分配密鑰;他們按升序排列。問題是，星期六和星期日不被視爲有效的營業日期，因此它們的值爲「9999」。在這種情況下，我想要做的是使用「9999」之後的行作爲「下一個」值，而不是使用具有「9999」的行。所以，用僞代碼解釋，我正在尋找類似的東西：

Case When nex.KEY = '9999' Then skip it and find the nex.KEY row that is not '9999' 
    Else CTE.NEXT_DT 
END AS Next 

我從一個CTE開始，但我對想法持開放態度。這裏是我現在能夠得到的輸出樣本。 「Next」列中的'9999'值是我正在更新的內容。

電流輸出：

rowNum DAY BUSINESS_DT KEY  PREV_DT  NEXT_DT  Previous Next 
3932 Sun 2015-09-13 9999 2015-09-11 2015-09-14 9999 2709 
3933 Mon 2015-09-14 2709 2015-09-11 2015-09-15 9999 2710 
3934 Tue 2015-09-15 2710 2015-09-14 2015-09-16 2709 2711 
3935 Wed 2015-09-16 2711 2015-09-15 2015-09-17 2710 2712 
3936 Thu 2015-09-17 2712 2015-09-16 2015-09-18 2711 2713 
3937 Fri 2015-09-18 2713 2015-09-17 2015-09-21 2712 9999 
3938 Sat 2015-09-19 9999 2015-09-18 2015-09-21 2713 9999 
3939 Sun 2015-09-20 9999 2015-09-18 2015-09-21 9999 2714 
3940 Mon 2015-09-21 2714 2015-09-18 2015-09-22 9999 2715 

所需的輸出：

rowNum DAY BUSINESS_DT KEY  PREV_DT  NEXT_DT  Previous Next 
3932 Sun 2015-09-13 9999 2015-09-11 2015-09-14 9999 2709 
3933 Mon 2015-09-14 2709 2015-09-11 2015-09-15 9999 2710 
3934 Tue 2015-09-15 2710 2015-09-14 2015-09-16 2709 2711 
3935 Wed 2015-09-16 2711 2015-09-15 2015-09-17 2710 2712 
3936 Thu 2015-09-17 2712 2015-09-16 2015-09-18 2711 2713 
3937 Fri 2015-09-18 2713 2015-09-17 2015-09-21 2712 **2714** 
3938 Sat 2015-09-19 9999 2015-09-18 2015-09-21 2713 **2714** 
3939 Sun 2015-09-20 9999 2015-09-18 2015-09-21 9999 2714 
3940 Mon 2015-09-21 2714 2015-09-18 2015-09-22 9999 2715 

下面是我的代碼：

WITH CTE AS 
(
Select 
rowNum = ROW_NUMBER() OVER(ORDER BY d.CALENDAR_DT_ID), 
d.DAY, 
d.KEY, 
d.BUSINESS_DT, 
d.PREV_DT, 
d.NEXT_DT, 
d.HOLIDAY_IN 
FROM CALENDAR_DT d 
) 

SELECT 
CTE.rowNum, 
CTE.DAY, 
CTE.BUSINESS_DT, 
CTE.KEY, 
CTE.PREV_DT, 
CTE.NEXT_DT, 
prev.KEY As Previous, 
nex.KEY As Next 

FROM CTE 
LEFT JOIN CTE prev ON prev.rownum = CTE.rownum - 1 
LEFT JOIN CTE nex ON nex.rownum = CTE.rownum + 1 
ORDER BY BUSINESS_DT 

Answer 1

SQL Fiddle Demo

;WITH CTE1 AS 
(
    SELECT ROW_NUMBER() OVER (ORDER BY CALENDAR_DT_ID) AS RN1, 
    DAY1, 
    BUSINESS_DT, 
    KEY1 
    FROM DATESCHART 
) 
,CTE2 AS 
(
    SELECT 1 AS SNO,1 AS RN2,* FROM CTE1 WHERE RN1=1 
    UNION ALL 
    SELECT CASE WHEN C1.KEY1=9999 THEN C2.SNO ELSE C2.SNO+1 END,RN2+1,c1.* 
    FROM CTE1 C1 INNER JOIN CTE2 C2 ON C1.RN1 = C2.RN2 
) 

SELECT C1.DAY1,C1.BUSINESS_DT,C1.KEY1,C3.BUSINESS_DT PREV_DT,C2.BUSINESS_DT NEXT_DT,C3.KEY1 PREVIOUS,C2.KEY1 NEXTK 
FROM CTE2 C1 LEFT JOIN CTE2 C2 ON C1.SNO+1 = C2.SNO AND C2.KEY1<>9999 
      LEFT JOIN CTE2 C3 ON C1.SNO-1 = C3.SNO AND C3.KEY1<>9999 
WHERE C1.RN2>1 

Answer 2

我想你可以改變的加盟條件nex和prev到使用日期而不是使用行號。

WITH CTE AS 
(
Select 
    rowNum = ROW_NUMBER() OVER(ORDER BY d.CALENDAR_DT_ID), 
    d.DAY, 
    d.KEY, 
    d.BUSINESS_DT, 
    d.PREV_DT, 
    d.NEXT_DT, 
    d.HOLIDAY_IN 
FROM CALENDAR_DT d 
) 
SELECT 
    CTE.rowNum, 
    CTE.DAY, 
    CTE.BUSINESS_DT, 
    CTE.KEY, 
    CTE.PREV_DT, 
    CTE.NEXT_DT, 
    prev.KEY As Previous, 
    nex.KEY As Next 
FROM CTE 
LEFT JOIN CTE prev 
ON CTE.PREV_DT = prev.BUSINESS_DT 
LEFT JOIN CTE nex 
ON CTE.NEXT_DT = nex.BUSINESS_DT 
ORDER BY BUSINESS_DT