0
我有兩個疑問:兩個查詢優化
SELECT `type`, COUNT(`id`) AS 'type' FROM `items` WHERE `post` = `id` GROUP BY `type`;
SELECT `type`, COUNT(`post`!=`id`) AS 'posts' FROM `items` GROUP BY `type`;
有沒有什麼辦法讓它在一個查詢?
我有兩個疑問:兩個查詢優化
SELECT `type`, COUNT(`id`) AS 'type' FROM `items` WHERE `post` = `id` GROUP BY `type`;
SELECT `type`, COUNT(`post`!=`id`) AS 'posts' FROM `items` GROUP BY `type`;
有沒有什麼辦法讓它在一個查詢?
如何像這樣
SELECT `type`,
COUNT(`post`=`id`),
COUNT(`post`!=`id`) AS 'posts'
FROM `items`
GROUP BY `type`;
查詢是確定的,但這樣的:!'COUNT('POST' ='id'),'返回完全相同的行值'COUNT('POST' = 'id')AS'posts''它不應該是這樣的,因爲'COUNT('post' ='id'),'這應該在第一行返回'5',但它返回'20',與此相同:'COUNT('post'!='id')AS'posts''。 – Isarius
你應該使用'SUM()'而不是'COUNT()'。 –
YE,這更有意義,可能在這兩種情況下? –