Modfying當前代碼

我的下一個任務是修改當前代碼。在之前的練習中，我寫了一個涵蓋數字猜測遊戲的基本應用程序。代碼如下： -Modfying當前代碼

# Guess My Number 
# 
# The computer picks a random number between 1 and 100 
# The player tries to guess it and the computer lets 
# the player know if the guess is too high, too low 
# or right on the money 

import random 

print("\tWelcome to 'Guess My Number'!") 
print("\nI'm thinking of a number between 1 and 100.") 
print("Try to guess it in as few attempts as possible.\n") 

# set the initial values 
the_number = random.randint(1, 100) 
guess = int(input("Take a guess: ")) 
tries = 1 

# guessing loop 
while guess != the_number: 
    if guess > the_number: 
     print("Lower...") 
    else: 
     print("Higher...") 

    guess = int(input("Take a guess: ")) 
    tries += 1 

print("You guessed it! The number was", the_number) 
print("And it only took you", tries, "tries!\n") 

input("\n\nPress the enter key to exit.")

我的任務是改變這一點，以便有一個數量有限的失敗消息是考慮到用戶之前的那張。到目前爲止，該章已經涵蓋了「if，elif，else，for，loops，避免無限循環」。因此，我只想限制我對這些概念的迴應。 For循環將在下一章介紹。

我試過了什麼？

到目前爲止，我已經嘗試在另一個while循環中修改該塊，使用5 go和try變量，但似乎不起作用。

# guessing loop 
while tries < 6: 
    guess = int(input("Take a guess: ")) 
    if guess > the_number: 
     print("Lower...") 
    elif guess < the_number: 
     print("Higher...") 
    elif guess == the_number: 
     print("You guessed it! The number was", the_number) 
     print("And it only took you", tries, "tries!\n") 
    break 
    tries += 1 

input("You didn't do it in time!") 
input("\n\nPress the enter key to exit.")

任何指針或突出顯示我已經錯過了什麼，將不勝感激加爲我已經錯過了任何解釋。教我自己去編程思考也是非常棘手的。

什麼不起作用 當我運行它時，循環條件似乎不起作用。我空閒的反饋如下。

這意味着我的問題可以概括爲我的循環邏輯在哪裏壞了？

>>> ================================ RESTART ================================ 
>>> 
    Welcome to 'Guess My Number'! 

I'm thinking of a number between 1 and 100. 
Try to guess it in as few attempts as possible. 

Take a guess: 2 
Take a guess: 5 
Higher... 
You didn't do it in time! 


Press the enter key to exit.

來源

2013-03-01 Steven D Andrews

您需要定義「似乎不起作用」*表示*。它會給出錯誤嗎？你的輸出是否與你的期望不符？請*包括*那些期望和你得到的輸出是什麼。 – 2013-03-01 16:08:05

不是真正的問題（有什麼問題？）/離題（代碼評論在codereviews.stackexchange.com上） – rds 2013-03-01 16:09:44

順便說一句，你可以通過使用'for'循環代替'while '循環，並擺脫'try'變量。只要將範圍（6）：'中的'嘗試<6：'行更改爲''即可。 – 2013-03-01 16:11:06

的問題是，你的break聲明沒有縮進被包含在elif：

elif guess == the_number: 
    print("You guessed it! The number was", the_number) 
    print("And it only took you", tries, "tries!\n") 
break

因此，該循環總是在第一次迭代後停止。縮進break以包含在elif之內，它應該可以工作。

來源

2013-03-01 16:08:10

休息不在條件。在它之前添加一個選項卡。

來源

2013-03-01 16:10:11 xylon97

Modfying當前代碼

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