如何爲每個組排序（PostgreSQL）

Question

有一個組號碼，每個組有幾個inst號碼。 我需要根據狀態值對查詢結果進行排序。 如果組內狀態列的值爲'ABNORMAL'，則屬於該組的總行應打印在上面，就像所需的結果一樣。 我想到了聯盟所有，但我沒有看到正確的。

你能幫我解決這個問題嗎？

@ DDL/DML

CREATE TABLE test.sort_test 
(
    group_number integer, 
    inst_number integer, 
    status1 character varying, 
    status2 character varying  
); 

INSERT INTO test.sort_test VALUES(0,0,'NORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(0,1,'NORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(0,2,'NORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(0,3,'NORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(1,0,'ABNORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(1,1,'NORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(1,2,'NORMAL','NORMAL'); 
INSERT INTO test.sort_test VALUES(2,0,'NORMAL','ABNORMAL'); 

@原始查詢

select * 
from test.sort_test 
order by group_number, inst_number 

0 0 "NORMAL" "NORMAL" 
0 1 "NORMAL" "NORMAL" 
0 2 "NORMAL" "NORMAL" 
0 3 "NORMAL" "NORMAL" 
1 0 "ABNORMAL" "NORMAL" 
1 1 "NORMAL" "NORMAL" 
1 2 "NORMAL" "NORMAL" 
2 0 "NORMAL" "ABNORMAL" 

@期望的結果

1 0 "ABNORMAL" "NORMAL" 
1 1 "NORMAL" "NORMAL" 
1 2 "NORMAL" "NORMAL" 
2 0 "NORMAL" "ABNORMAL"   
0 0 "NORMAL" "NORMAL" 
0 1 "NORMAL" "NORMAL" 
0 2 "NORMAL" "NORMAL" 
0 3 "NORMAL" "NORMAL"  

Answer 1

select group_number, inst_number, status1, status2 
from 
    sort_test 
    inner join (
     select group_number, bool_or('ABNORMAL' in (status1, status2)) as abnormal 
     from sort_test 
     group by group_number 
    ) s using (group_number) 
order by not abnormal, group_number, inst_number 
; 
group_number | inst_number | status1 | status2 
--------------+-------------+----------+---------- 
      1 |   0 | ABNORMAL | NORMAL 
      1 |   1 | NORMAL | NORMAL 
      1 |   2 | NORMAL | NORMAL 
      2 |   0 | NORMAL | ABNORMAL 
      0 |   0 | NORMAL | NORMAL 
      0 |   1 | NORMAL | NORMAL 
      0 |   2 | NORMAL | NORMAL 
      0 |   3 | NORMAL | NORMAL 

bool_or爲真，如果在條件中任一爲真該組的行。