php，mysqli從表中使用按鈕獲取數據

Question

我卡在點...如何從單行diplayed表格格式獲取數據？

這裏是我的代碼：

$raw = mysql_query("SELECT * FROM tbl"); 
$allresults = mysql_fetch_array($raw); 

while($raw = mysql_fetch_assoc($allresults)){ 
    echo $row['your field name here']; 
    echo "input type="submit" value="view""; 
} 

我去取用行旁邊的變量按鈕提供特定領域的數據。

Answer 1

$mysql = new mysqli("host", "user", "password", "DatabaseName"); 
$raw = $mysql->query("SELECT * FROM tbl"); 
while($someVariable = $raw->fetch_assoc()) { 
echo "$someVariable[field]"; 
} 

Answer 2

您不需要同時調用mysql_fetch_array（）和mysql_fetch_assoc（）函數。

嘗試這樣：

$allResults = mysql_query("SELECT * FROM tbl"); 
while($row = mysql_fetch_assoc($allResults)){ 
    echo $row['your field name here']; 
} 

這應該工作！