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我有3個文件 1）show_createtable.html 2）do_showfielddef.php 3）do_showtble.php
1）第一個文件是爲數據創建新表基地，它是一個2輸入，表名和字段數。這工作很好！
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<h1>Step 1: Name and Number</h1>
<form method="post" action="do_showfielddef.php" />
<p><strong>Table Name:</strong><br />
<input type="text" name="table_name" size="30" /></p>
<p><strong>Number of fields:</strong><br />
<input type="text" name="num_fields" size="30" /></p>
<p><input type="submit" name="submit" value="go to step2" /></p>
</form>
</body>
</html>
2）該腳本驗證字段並創建另一個表單來輸入所有的表格行。 這也適合工作！
<?php
//validate important input
if ((!$_POST[table_name]) || (!$_POST[num_fields])) {
header("location: show_createtable.html");
exit;
}
//begin creating form for display
$form_block = "
<form action=\"do_createtable.php\" method=\"post\">
<input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\">
<table cellspacing=\"5\" cellpadding=\"5\">
<tr>
<th>Field Name</th><th>Field Type</th><th>Table Length</th>
</tr>";
//count from 0 until you reach the number fo fields
for ($i = 0; $i <$_POST[num_fields]; $i++) {
$form_block .="
<tr>
<td align=center><input type=\"texr\" name=\"field name[]\"
size=\"30\"></td>
<td align=center>
<select name=\"field_type[]\">
<option value=\"char\">char</option>
<option value=\"date\">date</option>
<option value=\"float\">float</option>
<option value=\"int\">int</option>
<option value=\"text\">text</option>
<option value=\"varchar\">varchar</option>
</select>
</td>
<td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\">
</td>
</tr>";
}
//finish up the form
$form_block .= "
<tr>
<td align=center colspan=3><input type =\"submit\" value=\"create table\">
</td>
</tr>
</table>
</form>";
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Create a database table: Step 2</title>
</head>
<body>
<h1>defnie fields for <? echo "$_POST[table_name]"; ?>
</h1>
<? echo "$form_block"; ?>
</body>
</html>
問題是在這裏 3）這種形式創建的表和它們enteres到數據庫中。 我上線37得到一個錯誤「解析錯誤：語法錯誤，在/home/admin/domains/domaina.com.au/public_html/do_createtable.php意想不到的$結束的第37行」
<?
$db_name = "testDB";
$connection = @mysql_connect("localhost", "admin_user", "pass")
or die(mysql_error());
$db = @mysql_select_db($db_name, $connection)
or die(mysql_error());
$sql = "CREATE TABLE $_POST[table_name](";
for ($i = 0; $i < count($_POST[field_name]); $i++) {
$sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i];
if ($_POST[field_length][$i] !="") {
$sql .=" (".$_POST[field_length][$i]."),";
} else {
$sql .=",";
}
$sql = substr($sql, 0, -1);
$sql .= ")";
$result = mysql_query($sql, $connection) or die(mysql_error());
if ($result) {
$msg = "<p>" .$_POST[table_name]." has been created!</p>";
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Create A Database Table: Step 3</title>
</head>
<body>
<h1>Adding table to <? echo "$db_name"; ?>...</h1>
<? echo "$msg"; ?>
</body>
</html>
只是一個側面說明（如@Gumbo已經回答了你的問題），以呼應只是一個變量沒有必要與包圍嗎？「： 回聲」 $ db_name「; <=> echo $ db_name; 它更高效;） – maid450 2010-04-18 08:51:15