$嵌套ng中的索引值 - 如果內部的ng-repeat數組長度不同，則使用sequence重複

-1

我在angualrjs中使用嵌套的ng-repeat並且內部的ng-repeat數組長度不同。所以索引不會按順序顯示。我需要按順序輸出索引。我附上了輸出的截圖。

任何人都可以幫助我嗎？

<table class="table"> 
    <thead> 
      <th>#($index)</th> 
      <th>L #</th> 
      <th>C Name</th> 
      <th>A #</th> 
      <th>F P</th>       
    </thead> 
    <tbody ng-repeat="d in displayData" > 
     <tr ng-repeat="a in d.f_p track by $index" > 
      <td>{{($parent.$index*d.f_p.length)+($index+1)}}</td> 
      <td>{{d.lId}}</td> 
      <td>{{d.cName}}</td> 
      <td>{{$index+1}}</td> 
      <td>{{a}}</td>  
     </tr>  
</tbody> 
</table> 

$scope.displayData=[{"lId": "369857","cName": "ABCD","f_p":0.04401,0.04402,0.04403]},{"lId": "369858","cName": "BCDE",   "f_p":[0.04401,0.04402,0.04403,0.04404]},{"lId": "369859","cName": "CDEF",     "f_p":[0.04401,0.04402,0.04403,0.04404,0.04405]}];

來源

2016-09-26 sandy

您可以創建的jsfiddle，因爲你的JSON對象似乎無效 –

什麼是我們應該注意到截圖？問題不清楚，也不是你期望會有所不同 – charlietfl

這是NG-INIT，唯一有效的情況下：

<tbody ng-repeat="d in displayData" ng-init="$outerIndex = $index">

來源

2016-09-26 13:00:38

$嵌套ng中的索引值 - 如果內部的ng-repeat數組長度不同，則使用sequence重複

回答

相關問題