簡單的POST請求/響應方法？

Question

基本上，我想要做的就是使用我定義的一些POST變量來獲取PHP頁面的文本響應。

那麼，將一些POST數據（比如「arg1 = this & arg2 = that」）發送到URL並將響應（內容，不是標頭）作爲字符串處理的最簡單方法是什麼？

Answer 1

使用HttpUrlConnection使用java發送發佈請求。附上你的所有參數，並在test.php準備你的回覆並返回給發件人。

 import java.io.BufferedReader; 
     import java.io.DataOutputStream; 
     import java.io.InputStreamReader; 
     import java.net.HttpURLConnection; 
     import java.net.URL; 


     private void sendPost() throws Exception 
     { 

       String url = "http://example.com/test.php"; 
       URL obj = new URL(url); 
       HttpURLConnection con = (HttpURLConnection) obj.openConnection(); 

       //add reuqest header 
       con.setRequestMethod("POST"); 
       con.setRequestProperty("User-Agent", "Mozilla/5.0";); 
       con.setRequestProperty("Accept-Language", "en-US,en;q=0.5"); 

       String urlParameters = "para1= xxx & para2=yy"; 

       // Send post request 
       con.setDoOutput(true); 
       DataOutputStream wr = new DataOutputStream(con.getOutputStream()); 
       wr.writeBytes(urlParameters); 
       wr.flush(); 
       wr.close(); 

       int responseCode = con.getResponseCode(); 
       if(responseCode == HTTP_OK) 
       { 
       System.out.println("\nSending 'POST' request to URL : " + url); 
       System.out.println("Post parameters : " + urlParameters); 
       System.out.println("Response Code : " + responseCode); 

       BufferedReader in = new BufferedReader(
         new InputStreamReader(con.getInputStream())); 
       String inputLine; 
       StringBuffer response = new StringBuffer(); 

       while ((inputLine = in.readLine()) != null) { 
        response.append(inputLine); 
       } 
       in.close(); 

       //print result 
       System.out.println(response.toString()); 
        } 
       }