2015-09-05 42 views
1

一個WKInterfaceLabel的Text屬性我想鍵入InterfaceController if語句基本上去喜歡 -如何訪問Apple關注應用

if label.text == "Hello" { 
//execute some code 
} 

WKInterfaceLabel似乎只是有setText()財產。那麼如何訪問WKInterfaceLabel的文本屬性?提前致謝!

+0

回答每個問題的第一步:谷歌你遇到問題的類。這將永遠給你一個鏈接從蘋果與所有可用的功能,變量和類常量。 [WKInterfaceLabel類參考](https://developer.apple.com/library/prerelease/ios/documentation/WatchKit/Reference/WKInterfaceLabel_class/) –

回答

2

簡答:你不能。

較長的答案,將字符串存儲在一個單獨的變量中,並將其用於if語句。

class InterfaceController: WKInterfaceController { 

    @IBOutlet var myLabel: WKInterfaceLabel! 
    var myString : String = "" 

    override func awakeWithContext(context: AnyObject?) { 
     super.awakeWithContext(context) 

     myString = "hello" 
     myLabel.setText(myString) 

     if myString == "hello" { 

      //so awesome stuff here 

     } 
     // Configure interface objects here. 
    } 

    override func willActivate() { 
     // This method is called when watch view controller is about to be visible to user 
     super.willActivate() 
    } 

    override func didDeactivate() { 
     // This method is called when watch view controller is no longer visible 
     super.didDeactivate() 
    } 

} 
+0

再次感謝! –

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