給定一個日期（m/d/yyyy）來確定它的月份「第三個星期二」等。

Question

經過多次搜索，我一直無法找到我要找的東西。即時通訊使用jquery datepicker返回一個日期字符串，看起來像Day, Month Date, YYYY，我正在尋找一個庫或某種方法，將採取並將其變爲 the second Tuesday of the month或the fourth Thursday of the month。到目前爲止，它似乎像jquery的prettyDate和EasyDate沒有我正在尋找的功能，我很樂意避免這樣做的手！

謝謝， 亞歷克斯

Answer 1

這是我在天回用的腳本，如果momentjs不適合你的工作（雖然我真的覺得momentjs是一個更好的解決方案）。

/* 
Parameters: 
index: n'th occurrence of the specified day 
day: daynumber - javascript way where sunday is 0 and is saturday is 6 
month: javascript way which is 0-11 [optional - defaults to current] 
year: Full year - four digits [optional - defaults to current] 
*/ 
function getNthDayOfMonth(index,day,month,year){ 
// Create date object 
var date = new Date(); 
// Set to first day of month 
date.setDate(1); 
// If supplied - set the month 
if(month!==''&&month!==undefined){ 
    // Set month 
    date.setMonth(month); 
}else{ 
    month = date.getMonth(); 
} 
// If supplied - set the year 
if(year!==''&&year!==undefined){ 
    // Set year 
    date.setFullYear(year); 
}else{ 
    year = date.getFullYear(); 
} 
// Find daynumber 
firstDay = date.getDay(); 
// Find first friday. 
while(date.getDay()!=day){  
    date.setDate(date.getDate()+1) ; 
} 
switch(index){ 
    case 2: 
     date.setDate(date.getDate()+7);   
    break; 
    case 3: 
     date.setDate(date.getDate()+14);     
    break; 
    case 4: 
     date.setDate(date.getDate()+21); 
    break; 
    case 5: 
     date.setDate(date.getDate()+28); 
     if(date.getMonth()!==month){ 
      date = null; 
     } 
    break; 
} 
return date; 
} 

Answer 2

在Date.js你有一個像moveToFirstDayOfMonth和getWeek一些有用的功能。

然後，您可以獲取每月第一天的一週，並扣除這兩個月以獲取該月的一週。

下面是一個簡單的例子，使用Date.js，今天就離開，但你可以傳入你自己的日期。我對其他日期庫不太熟悉，但我認爲您可以重新創建下面的內容。

function dayOfWeekToday(){ 
    //Get the total weeks on the year from this day 
    var totalWeek = Date.today().getWeek(); 

    //Get the first day of this month 
    var firstOfMonth = Date.today().moveToFirstDayOfMonth(); 

    //Get the total weeks form the first day of the month 
    var weeksAtStartOfMonth = firstOfMonth.getWeek(); 
    //Get the week of the month 
    var week = totalWeek - weeksAtStartOfMonth; 

    //Get the day(0-6) of today and the first day 
    var today = Date.today().getDay(); 
    var firstDay = firstOfMonth.getDay(); 

    //If today is before the firstDay then the week will be off by one 
    if(today < firstDay){ 
     week--; 
    } 
    //Get the day form of the string 
    var day = Date.today().toString("dddd"); 

    //Translate from a number to a string 
    var str = "first"; 
    if(week === 1){ 
      str = "second"; 
    }else if(week === 2){ 
     str = "third"; 
    }else if(week === 3){ 
     str = "fourth"; 
    }else if (week === 4){ 
     str = "fifth"; 
    } 
    //Result 
    return "The "+str+" "+day+" of the month"; 
} 

Answer 3

我寫了一些簡單的邏輯，只是倒過來從日期的值：

function calculateNthDate(startDateDay, startDateValue){ 
    var day = startDateDay; 
    var date = startDateValue; 
    var i = 0; 

    while(date >= 0){ 

     if (date > 0){ 
      i++; 
     } 
     date = date - 7; 
    } 
    var string = "The "+i+'th '+day+" of the month."; 
} 

編輯：th將不得不進行自定義nd，st和rd。

Answer 4

你不需要一個日期庫 - 只取日期，除以7並四捨五入。

//format: Day, Month Date, YYYY 
var ordinals = ["", "first", "second", "third", "fourth", "fifth"]; 
var date = "Friday, May 10, 2013"; 
var tokens = date.split(/[ ,]/); 
// tokens = ["Friday", "", "May", "10", "", "2013"]; 
console.log("The " + ordinals[Math.ceil(tokens[3]/7)] + " " + tokens[0] + " of the month"); 

Answer 5

function nthDay(D){ 
    var nth= ['First', 'Second', 'Third', 'Fourth', 'Fifth'], 
    dayNames= ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 
    'Thursday', 'Friday', 'Saturday'], 
    monthNames= ['January', 'February', 'March', 'April', 'May', 'June', 
    'July', 'August', 'September', 'October', 'November', 'December']; 

    return nth[Math.floor(D.getDate()/7)]+' '+ 
    dayNames[D.getDay()]+' of '+monthNames[D.getMonth()]; 
} 

nthDay（新日期（2013年，4，10））

/*返回值：五月 的 第二個星期五*/