0
如何從不使用CodeIgniter表單創建的表單驗證輸入數據?CodeIgniter中HTML表單數據的表單驗證
我的形式如下:
<form method="POST" name="frmNewUser" action="<?php echo site_url('users/signup'); ?>" id="contact">
\t \t <div class="lable">
\t \t <div class="col_1_of_2 span_1_of_2"><input name="u_fname" type="text" class="text" value="First Name" onfocus="this.value = '';" onblur="if (this.value == '') {this.value = 'First Name';}" id="active"></div>
<div class="col_1_of_2 span_1_of_2"><input name="u_lname" type="text" class="text" value="Last Name" onfocus="this.value = '';" onblur="if (this.value == '') {this.value = 'Last Name';}"></div>
<div class="clear"> </div>
\t \t </div>
\t \t <div class="lable-2">
\t \t <input name="u_email" type="text" class="text" value="[email protected] " onfocus="this.value = '';" onblur="if (this.value == '') {this.value = '[email protected] ';}">
\t \t <input name="u_pwd" type="password" class="text" value="Password " onfocus="this.value = '';" onblur="if (this.value == '') {this.value = 'Password ';}">
\t \t </div>
\t \t <h3>By creating an account, you agree to our <span class="term"><a href="#">Terms & Conditions</a></span></h3>
\t \t <div class="submit">
\t \t \t <input type="submit" name="submit" id="submit" value="Submit" >
\t \t </div>
\t \t <div class="clear"> </div>
\t \t </form>
這裏是我的控制器:
function signup(){
$this->load->library('form_validation');
$u_fname = $this->input->post('u_fname');
$u_lname = $this->input->post('u_lname');
$u_email = $this->input->post('u_email');
$u_pwd = $this->input->post('u_pwd');
$this->form_validation->set_rules($this->input->post('u_fname'), 'First Name', 'required');
if($this->form_validation->run() == FALSE){
echo "error";
}
}
然而的run()form_validation的函數返回即使u_fname有假輸入值。 如何使用post方法從表單中獲取數據並使用CodeIgniter中的form_validation驗證數據?
謝謝