8
#include <iostream>
#include <string>
constexpr std::string appendStringC(std::string s)
{
return s + " Constexpr func";
}
std::string appendString(std::string s)
{
return s + " Regular func";
}
int main()
{
std::string s1 = "String 1";
std::string s2 = "String 2";
std::cout << std::endl
<< appendStringC(s1) << std::endl
<< appendString(s2) << std::endl;
return 0;
}
我試圖執行使用constexpr編譯時間字符串前綴/後綴串聯操作。然而,這個例子產生以下錯誤:編譯時字符串連接constexpr
const_string_generation.cpp: In function ‘constexpr std::__cxx11::string appendStringC(std::__cxx11::string)’:
const_string_generation.cpp:4:23: error: invalid type for parameter 1 of constexpr function ‘constexpr std::__cxx11::string appendStringC(std::__cxx11::string)’
constexpr std::string appendStringC(std::string s)
^
In file included from /usr/include/c++/5.3.0/string:52:0,
from /usr/include/c++/5.3.0/bits/locale_classes.h:40,
from /usr/include/c++/5.3.0/bits/ios_base.h:41,
from /usr/include/c++/5.3.0/ios:42,
from /usr/include/c++/5.3.0/ostream:38,
from /usr/include/c++/5.3.0/iostream:39,
from const_string_generation.cpp:1:
/usr/include/c++/5.3.0/bits/basic_string.h:71:11: note: ‘std::__cxx11::basic_string<char>’ is not literal because:
class basic_string
^
/usr/include/c++/5.3.0/bits/basic_string.h:71:11: note: ‘std::__cxx11::basic_string<char>’ has a non-trivial destructor
const_string_generation.cpp:4:23: error: invalid return type ‘std::__cxx11::string {aka std::__cxx11::basic_string<char>}’ of constexpr function ‘constexpr std::__cxx11::string appendStringC(std::__cxx11::string)’
constexpr std::string appendStringC(std::string s)
因爲std :: string不是一個文字。我正在尋找一個簡單的方法來做到這一點,我不關心這個例子的後向兼容性。 Ideone:Link
你不能,因爲'std :: string'通常在內部使用動態分配(不是很「constexpr」友好)。但是,您可以通過將它們依次放置來連接兩個或多個字符串*文字*。 –
@ Cheersandhth.-Alf是的,但我有很多很長的字符串,我需要在前面或有時在字符串後面連接。有點像轉義碼,所以手動放置和編輯它們中的每一個都可能很快變得笨拙。 –
你可以使用字符序列,像http://stackoverflow.com/a/22067775/2684539 – Jarod42