修復while循環

Question

如何修復此代碼中的while循環，以便僅在age爲18時工作，如果小於此值則打印出錯信息，並且即使在錯誤的郵政編碼之後仍然繼續執行程序？

這裏是我的代碼：

print "VOTER ELIGIBILITY AND POLLING STATION PROGRAM" 
print 
print 
age= int(raw_input("Enter your age (Type ' 0 ' to exit program) :")) 
while age != 18: 
    print "ineligible" 
    age= int(raw_input("Enter your age (Type ' 0 ' to exit program) :")) 
    if age != 0: 
     zipcode= int(raw_input("Enter your residence's zip code:")) 

     if zipcode == 93305: 
      print "Your polling station is 123 Panorama Drive." 
     elif zipcode == 93306: 
      print "Your polling station is 6143 Fairfax Drive." 
     elif zipcode ==93307: 
      print "Your polling station is 21121 B Street." 
     elif zipcode ==93308: 
      print "Your polling station is 863 Desmond Ct." 
     elif zipcode == 93309: 
      print "Your polling station is 7332 Del Canto Ct." 
     else: 
      print "Error-unknown zip code" 

raw_input("\nRun complete.Press the Enter key to exit.")  

Answer 1

嘗試類似：

age = get_age(); 

while (age != 0) { 
    if (age >= 18) ... 
    else ... 

    age = get_age(); 
} 

exit