分數類故障排除

Question

作爲一項任務，我應該爲分數創建一個Rational類，並重載各種操作符以操縱分數。但我在清理如何做這件事方面遇到了很多麻煩。這是我的代碼和當前的錯誤消息。任何幫助將不勝感激！

編輯：感謝您的幫助。它仍然有兩個錯誤消息。 一噸（14+）的實例：未定義的引用'Rational :: Rational（）' 2：當我超載< <運算符它說num和den沒有定義。我如何告訴它從它應該打印出來的對象中獲取數字和書房？ 謝謝！

頭文件

#ifndef Rational_H 
#define Rational_H 

#include<iostream> 
#include <string> 
using namespace std; 

class Rational 
{ 

    friend Rational operator+(const Rational& x1, const Rational& x2); 
    friend Rational operator-(const Rational& x1, const Rational& x2); 
    friend Rational operator*(const Rational& x1, const Rational& x2); 

public: 
    Rational(); //constructor 
    void setFraction(int, int); //set fractional 
    int getNum() const; 
    int getDen() const; 

    void RSimplify(); 
    void printFraction(); 
    friend ostream &operator<<(ostream &, const Rational &); 
    friend istream &operator>>(istream &, Rational &); 

private: 
    int num; 
    int den; 
}; 

#endif 

.cpp文件

#include <iomanip> 
#include "Rational.h" 
using namespace std; 


int Rational::getNum() const 
{ 
    return num; 
} 

int Rational::getDen() const 
{ 
    return den; 
} 

ostream &operator<<(ostream &output, const ATJRational &ATJRational) 
{ 
    return output << num << "/" << den; 
Error: num and den are not declared in this scope 
} 
istream &operator>>(istream &input, ATJRational &ATJRational) 
{ 
    char slash; 
    return input >> ATJRational.num >> slash >> ATJRational.den; 
    ATJRational.RSimplify(); 
} 

void ATJRational::RSimplify() 
{ 
    for(int i=2; i<14; i++) 
    { 
     while(den % i == 0) 
     { 
      if(num % i == 0) 
      { 
       den = den/i; 
       num = num/i; 
      } 
     } 
    } 
} 


Rational operator+(const Rational& x1, const Rational& x2) 
    { 
    Rational x3;  
    x3.num = (x1.num * x2.den) + (x2.num * x1.den); 
    x3.den = (x1.den * x2.den); 
    x3.RSimplify(); 
    return x3; 
    } 

Rational operator-(const Rational& x1, const Rational& x2) 
    { 
    Rational x3;  // result 
    x3.num = (x1.num * x2.den) - (x2.num * x1.den); 
    x3.den = (x1.den * x2.den); 
    x3.RSimplify(); 
    return x3; 
    } 

Rational operator*(const Rational& x1, const Rational& x2) 
    { 
    Rational x3;  // result 
    x3.num = (x1.num * x2.num); 
    x3.den = (x1.den * x2.den); 
    x3.RSimplify(); 
    return x3; 
    } 

主文件

#include <iostream> 
#include "Rational.h" 
using namespace std; 

int main() 
{ 
    Rational x1; //create object fraction 
    Rational x2; 
    Rational x3; 

    cout<<"Enter a fraction in the form 1/4:"<<endl; 
    cin>>x1; 

    cout<<"Enter a 2nd fraction in the form 1/4:"<<endl; 
    cin>>x2; 

    cout<<"The two fractions in their lowest terms are: "<<x1<<" and "<<x2<<endl; 

    cout<<"Adding the 1st and 2nd fractions together..."<<endl; 
    x3 = x1 + x2; 
    cout<<"The sum of the two fractions is:"<<x3<<endl; 

    cout<<"Subtracting the 1st fraction from the 2nd fraction..."<<endl; 
    x3 = x2 - x1; 
    cout<<"The result is:"<<x3<<endl; 

    cout<<"Multiplying the 1st fraction by the 2nd fraction..."<<endl; 
    x3 = x1 * x2; 
    cout<<"The product is:"<<x3<<endl; 

} 

Answer 1

忽略任何邏輯錯誤，我可以看到一些問題。可能還有更多。

首先，這

RSimplify.x3; 

應該

x3.RSimplify(); 

其次，你的算術運算符的定義不匹配的朋友的聲明。這是因爲丟失了一個RHS const：

Rational operator+(const Rational& x1, Rational& x2) { .... } 

必須

Rational operator+(const Rational& x1, const Rational& x2) { .... } 

三，輸出流操作者應作用於你通過它的流，沒有明確cout。所以，

ostream &operator<<(ostream &output, const Rational &Rational) 
{ 
    return output << num << "/" << den; 
} 

注意它也是明智的，它留給呼叫者添加endl或其他任何東西。