兩個日期戳，在每一天之間響應

Question

好的說，我有兩個時間戳以格式yyyymmdd保存在數據庫中，一個開始日期和結束日期。

說的這些都是我的開始和結束日期：20110618-20110630

我怎麼會讓它回聲20110618，20110619，20110620等一路20110630？

Answer 1

// Will return the number of days between the two dates passed in 
function count_days($a, $b) { 
    // First we need to break these dates into their constituent parts: 
    $gd_a = getdate($a); 
    $gd_b = getdate($b); 

    // Now recreate these timestamps, based upon noon on each day 
    // The specific time doesn't matter but it must be the same each day 
    $a_new = mktime(12, 0, 0, $gd_a['mon'], $gd_a['mday'], $gd_a['year']); 
    $b_new = mktime(12, 0, 0, $gd_b['mon'], $gd_b['mday'], $gd_b['year']); 

    // Subtract these two numbers and divide by the number of seconds in a 
    // day. Round the result since crossing over a daylight savings time 
    // barrier will cause this time to be off by an hour or two. 
    return round(abs($a_new - $b_new)/86400); 
} 

// Prepare a few dates 
$date1 = strtotime('20110618'); 
$date2 = strtotime('20110630'); 

// Calculate the differences, they should be 43 & 11353 
echo "<p>There are ", count_days($date1, $date2), " days.</p>\n"; 
$days = count_days($date1, $date2); 
for ($i = 0; $i < $days; $i++) { 
    echo date('Ymd', $date1+(86400*$i)); 
} 

從使用功能：Get number of days between two dates。

Answer 2

使用PHP DateTime對象，所以下面將是persudo代碼

//Convert the 2 dates to a php datetime object 
//Get the number of days differance inbetween 
//For each day, 
     //create a new datetime object, N days after the youngest object 
     //Echo the reasult out 

Answer 3

你就不能這樣做： （編輯以包括實際的PHP環路）

$date = new DateTime('20110618'); 
do { 
    $d = $date->format('Ymd') . "\n"; 
    echo $d; 
    $date->add(new DateInterval('P1D')); 
} while ($d < 20110630); 

Answer 4

這應該打印的所有日期爲您在PHP 5.3

$start = '20110618'; 
$end = '20110630'; 

$date = new DateTime($start); 
$end = new DateTime($end)->getTimestamp(); 

while ($date->getTimestamp() <= $end) { 
    echo $date->format('Ymd'); 
    $date->add(new DateInterval('P1D')); 
}