來自MySQL的PHP​​可用性檢查Jquery

Question

我有一個網上書店，我出售書籍。我在這裏存儲購物車的數據。當選擇兩本或更多本書時，可能沒有全部可用的書。我只能檢查一本可用或不可用的書。但是，當兩本或兩本以上的書籍被選中訂購時，我無法完成。我爲一本書做的是：

$result = mysql_query("SELECT id FROM book_table WHERE id IN ($cart)"); 
while ($row = mysql_fetch_array($result)) { 
    $q=mysql_num_rows(mysql_query("SELECT available FROM book_table WHERE id='$row[0]'")); 
    if($q!=0){ 
     //order goes fore processing. 
    } 
    else{ 
     //books not available. 
     $q2=mysql_fetch_array(mysql_query("SELECT name FROM book_table WHERE id='$row[0]'")); 
     echo "The book: $q2[0] Not Available"; 
     //If there is more than 1 books in the cart and one or two books of them are not in the stock, its showing the order cant be processed(But I want to show which books aren't available). 
    } 
} 

這裏$購物車是保存在像1,2,3,4會話的書籍車。 現在我需要通過重定向到另一個頁面來顯示哪些書無法購買。

任何人都可以幫我解決這個問題嗎？

Answer 1

你可以像下面，

$query=mysql_query("SELECT id,available FROM book_table WHERE id IN ($cart) "); 
$books_available_num = mysql_num_rows($query); 
$books_order_num = count(explode(",",$cart));//i think there should be better way to do this... 
if($books_available_num==0){ 
    //no book is available 
}elseif($books_available_num==$books_order_num){ 
    //all books are available 
    while($fetch=mysql_fetch_array($query)){ 
     //order done successfully. 
    } 

}else{ 
    //some are available some are not. 
    while($fetch=mysql_fetch_array($query)){ 
     if($fetch['status']=="available"){ 
      //place in order 
     }else{ 
      //this is not available 
     } 
    } 
} 
//rest of code. I think now you can do yourself. 

我告訴你的方法，你可以提高自己。代碼可能包含錯誤，您可以改進它。

Answer 2

創建一個數組並將id和availaibilty作爲鍵和值對，並檢查每個id的可用性。

Answer 3

您可以使用Ajax就像沒有重定向到其他頁面

$.ajax({ 
      url  :'yourpage.php', 
      type :'post', 
      sucess : function(data){ alert(data)} 
     }) 

和你的PHP代碼需要一點修改

$result = mysql_query("SELECT id FROM book_table WHERE id IN ($cart)"); 
    $error = array(); 
while ($row = mysql_fetch_array($result)) { 
$q=mysql_num_rows(mysql_query("SELECT available FROM book_table WHERE id='$row[0]'")); 
if($q!=0){ 
    //order goes fore processing. 
} 
else{ 
    //books not available. 
    $q2=mysql_fetch_array(mysql_query("SELECT name FROM book_table WHERE id='$row[0]'")); 
    $error[] = "The book: $q2[0] Not Available"; 
    //If there is more than 1 books in the cart and one or two books of them are not in the stock, its showing the order cant be processed(But I want to show which books aren't available). 
} 

    if (!empty(error)) 
    { 
     // print array as you want 
    } 
    else 
    { 
     echo "order successfully placed" 
    } 
} 

看到更多關於jquery ajax

，如果你想這樣做在會話中重定向到其他頁面$error。 我不認爲任何其他東西可以幫助你

注意：避免使用mysql_ *，因爲他們已被棄用

Answer 4

$all_available = true; 
$orders = array(); 
$result = mysql_query("SELECT id, available, name FROM book_table WHERE id IN ($cart)"); 
while ($row = mysql_fetch_assoc($result)) { 
    if ($row['available')) { 
    $orders[] = $row['id']; 
    } else { 
    $all_available = false; 
    echo "The book: " . $row['name'] . " is not available.\n" 
    } 
} 
if ($all_available) { 
    // Process $orders 
} else { 
    // Send redirect 
}