0
我想用mysql數據庫在php中編碼,並且我想用儲值和新的輸入值來計算餘額。例如我有數據庫是這樣的:PHP - 用以前的值計算餘額
id | debit | credit | balance
----+---------+--------+--------
1 | 70000 | 0 | 70000
2 | 0 | 44000 | 26000
3 | 45000 | 15000 | 56000
4 | 0 | 32000 | 24000
5 | 0 | 10000 | 14000
6 | 28000 | 0 | 42000
式是balance = old_balance + new_inputed_debit - new_inputed_credit
所以,如果我在HTML形式inputed這樣新值:
借記= 30000
信用= 5000
因此,當我單擊輸入按鈕時,腳本將對此進行求和balance = 42000 + 30000 - 5000
和數據庫會變成這個樣子:
id | debit | credit | balance
----+---------+--------+--------
1 | 70000 | 0 | 70000
2 | 0 | 44000 | 26000
3 | 45000 | 15000 | 56000
4 | 0 | 32000 | 24000
5 | 0 | 10000 | 14000
6 | 28000 | 0 | 42000
7 | 30000 | 5000 | 67000 <-- New Submited Value
這是我的PHP腳本:
<?php
require('db2.php');
// If form submitted, insert values into the database.
if(isset($_POST['submit'])) {
$debit = mysqli_real_escape_string($con,$_POST['debit']);
$credit = mysqli_real_escape_string($con,$_POST['credit']);
$balance = //old_balance + new_inputed_debit - new_inputed_credit
$query = "INSERT into `balance` (debit, credit, balance,) VALUES ('$debit','$credit', '$balance')";
if(mysqli_query($con,$query)){
echo "<div class='form'><h3>Inputed Success</h3><br/><a href='Input.php'>Input again</a></div> or <a href='index.php'>back</a>";
}else{
}
}
?>
,這是我的html代碼:
<form name="input_data" action="" method="post"><br />
<label style="font-size:16px;">Debit :</label>
<input type="text" name="debit" placeholder="Ex: 90000" style="margin-left:3px; width:80% !important;" required /><br />
<label style="font-size:16px;">Credit :</label>
<input type="text" name="credit" placeholder="Ex: 90000" style="margin-left:3px; width:80% !important;" required /><br />
<span style="float:right;"><input type="reset" name="reset" value="RESET" style="margin-right:8px;" /> <input type="submit" name="submit" value="INPUT" style="margin-right:8px;" /></span>
</form>
是否有人可以幫助我創建php腳本?謝謝。
收到錯誤:)mysqli_num_rows(預計參數1被mysqli_result,在balance.php定的boolean – RA121514
改變你的表名或列名從「平衡」到任何其他名稱,並嘗試在執行選擇查詢phpmyadmin檢查它是否返回任何數據。 –
當您的查詢未成功執行時,會出現此錯誤。所以按照上面的評論做 –