這是我在以前版本的雨燕的可行代碼:如何將數組轉換爲UnsafeMutablePointer <UnsafeRawPointer?> Swift 3.0?
let imageOptionsDictKeys = [ kCVPixelBufferPixelFormatTypeKey, kCVPixelBufferWidthKey, kCVPixelBufferHeightKey, kCVPixelBufferOpenGLESCompatibilityKey, kCVPixelBufferIOSurfacePropertiesKey]
let imageOptionsDictValues = [ cvPixelFormatType, frameW, frameH, boolYES]
var keyCallbacks = kCFTypeDictionaryKeyCallBacks
var valueCallbacks = kCFTypeDictionaryValueCallBacks
let imageOptions = CFDictionaryCreate(kCFAllocatorDefault, UnsafeMutablePointer(imageOptionsDictKeys), UnsafeMutablePointer(imageOptionsDictValues), 4, &keyCallbacks, &valueCallbacks)
後的雨燕3.0的變化我必須將我的鑰匙和值數組到UnsafeMutablePointer<UnsafeRawPointer?>
創建CFDictionary。
這樣:
let imageOptionsDictKeysPointer = UnsafeMutablePointer<UnsafeRawPointer?>.allocate(capacity: 1)
imageOptionsDictKeysPointer.initialize(to: imageOptionsDictKeys)
給出了一個錯誤訪問錯誤。
和閱讀文檔後,我試圖編譯這段代碼:
let imageOptionsDictKeys = [kCVPixelBufferPixelFormatTypeKey, kCVPixelBufferWidthKey, kCVPixelBufferHeightKey, kCVPixelBufferOpenGLESCompatibilityKey]
let imageOptionsDictKeysRawPointer = Unmanaged.passUnretained(imageOptionsDictKeys).toOpaque()
let imageOptionsDictKeysPointer = UnsafeMutablePointer<UnsafeRawPointer?>.allocate(capacity: 1)
imageOptionsDictKeysPointer.initialize(to: imageOptionsDictKeysRawPointer)
let imageOptionsDictValues = [ cvPixelFormatType, frameW, frameH, boolYES]
let imageOptionsDictValuesRawPointer = Unmanaged.passUnretained(imageOptionsDictValues).toOpaque()
let imageOptionsDictValuesPointer = UnsafeMutablePointer<UnsafeRawPointer?>.allocate(capacity: 1)
imageOptionsDictValuesPointer.initialize(to: imageOptionsDictValuesRawPointer)
let imageOptions = CFDictionaryCreate(kCFAllocatorDefault, imageOptionsDictKeysPointer, imageOptionsDictValuesPointer, 4, &keyCallbacks, &valueCallbacks)
但錯誤泛型參數「實例」無法在行Unmanaged.passUnretained(陣列)推斷出現。 toOpaque()
我不知道如何以編程方式現在創建CFDictionary。
不創建CFDictionary。改爲創建一個Swift Dictionary,例如:http://stackoverflow.com/a/38171414/1187415。 –
我必須用CFDictionary參數調用函數VTCompressionSessionCreate(....)。我不確定我可以只使用Swift Dictionary ...或者它們可以以某種方式轉換嗎? – JULIIncognito
似乎是一種不必要的複雜方式來製作一個'CFDictionary',和一本教科書[XY Problem](http://xyproblem.info)。請參閱http://stackoverflow.com/q/29301302/3141234 – Alexander