我已經構建了一個可以登錄用戶並獲得他們的ID的firebase應用程序,但我無法弄清楚如何將這個與用戶提交字符串進行合併。如何使用angularfire將輸入與Firebase中的用戶相關聯?
見代碼筆在這裏:http://codepen.io/chriscruz/pen/OPPeLg
HTML以下:
<html ng-app="fluttrApp">
<head>
<script src="https://code.jquery.com/jquery-2.1.1.min.js"></script>
<script src="https://code.jquery.com/ui/1.11.1/jquery-ui.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.2/angular.min.js"></script>
<script src="https://cdn.firebase.com/js/client/2.0.2/firebase.js"></script>
<script src="https://cdn.firebase.com/libs/angularfire/0.9.0/angularfire.min.js"></script>
</head>
<body ng-controller="fluttrCtrl">
<button ng-click="auth.$authWithOAuthPopup('google')">Login with Google</button>
<li>Welcome, {{user.google.displayName }}</li>
<button ng-click="auth.$unauth()">Logout with Google</button>
<input ng-submit= "UpdateFirebaseWithString()" ng-model="string" ></input>
的Javascript下面:
<script>
var app = angular.module("fluttrApp", ["firebase"]);
app.factory("Auth", ["$firebaseAuth", function($firebaseAuth) {
var ref = new Firebase("https://crowdfluttr.firebaseio.com/");
return $firebaseAuth(ref);
}]);
app.controller("fluttrCtrl", ["$scope", "Auth", function($scope, Auth) {
$scope.auth = Auth;
$scope.user = $scope.auth.$getAuth();
$scope.UpdateFirebaseWithString = function() {
url = "https://crowdfluttr.firebaseio.com/ideas"
var ref = new Firebase(url);
var sync = $firebaseAuth(ref);
$scope.ideas = sync.$asArray();
$scope.ideas.$add({
idea: $scope.string,
userId:$scope.user.google.id,
});
};
}])
</script>
</body>
</html>
而且假設,上述的依賴,下面的工作提出想法,但這個問題仍然存在於如何將這與用戶聯繫起來。看看這裏codepen:http://codepen.io/chriscruz/pen/raaENR
<body ng-controller="fluttrCtrl">
<form ng-submit="addIdea()">
<input ng-model="title">
</form>
<script>
var app = angular.module("fluttrApp", ["firebase"]);
app.controller("fluttrCtrl", function($scope, $firebase) {
var ref = new Firebase("https://crowdfluttr.firebaseio.com/ideas");
var sync = $firebase(ref);
$scope.ideas = sync.$asArray();
$scope.addIdea = function() {
$scope.ideas.$add(
{
"title": $scope.title,
}
);
$scope.title = '';
};
});
</script>
</body>