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嗨,我想要從一個網頁源獲取所有標題。所以,我嘗試使用PHP的XPath和我寫的:Php Xpath - 從代碼源獲取標題
$dom = new DOMDocument();
@$dom->loadHTMLFile('http://some-site.com/egypt/book-shops');
$xpath = new DOMXPath($dom);
$entries = $xpath->query("//td[@class='icon']/i/@title");
foreach($entries as $e) {
echo 'Title is : ' . $e->textContent . '<br />';
}
網頁源代碼是:
<td class="icons">
<i title="[email protected]" data-shopnameid="Good Life" class="icon email-small message-shop" id="message-shop-8"></i>
... ... ...
我哪裏錯了,是什麼錯誤。我只是白屏。
看得那麼清楚:?參考 - 這是什麼錯誤PHP的意思(http://stackoverflow.com/q/12769982/367456 ) – hakre 2014-10-12 12:10:08