JPA Like子句不起作用

Question

我嘗試以下操作，但LIKE篩選器未應用，即返回完整的結果集。請有任何想法嗎？正如你可以在下面的日誌中看到的那樣，LIKE標準在那裏，但我猜這些參數沒有被填充。

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder(); 
    CriteriaQuery<T> criteriaQuery = criteriaBuilder.createQuery(typeParameterClass); 

    // from 
    Root<T> from = criteriaQuery.from(typeParameterClass); 
    criteriaQuery.select(from); 

    // like 
    if (searchQuery != null && searchQuery.trim().length() > 0) { 
     List<Predicate> predicates = new ArrayList<Predicate>(); 
     for (String name : getColumnNames(typeParameterClass)) { 
      Predicate condition = criteriaBuilder.like(from.<String>get(name), "%" + searchQuery + "%"); 
      predicates.add(condition); 
     } 
     criteriaQuery.where(criteriaBuilder.or(predicates.toArray(new Predicate[] {}))); 
    } 

    List<T> results = (List<T>) entityManager.createQuery(criteriaQuery).setFirstResult(firstResult) 
      .setMaxResults(maxResults).getResultList(); 
    return results; 

日誌：

select 
employee0_.id as id1_1_, 
employee0_.AVATAR as AVATAR2_1_, 
employee0_.AVERAGE_RATING as AVERAGE_3_1_, 
employee0_.DISTANCE as DISTANCE4_1_, 
employee0_.DRIVERS_LICENCE as DRIVERS_5_1_, 
employee0_.EMAIL_ADDRESS as EMAIL_AD6_1_, 
employee0_.FIRST_NAME as FIRST_NA7_1_, 
employee0_.JOB_DESCRIPTION as JOB_DESC8_1_, 
employee0_.JOB_DETAILS as JOB_DETA9_1_, 
employee0_.JOB_TITLE as JOB_TIT10_1_, 
employee0_.JOINING_DATE as JOINING11_1_, 
employee0_.LASTACCESS_DATE as LASTACC12_1_, 
employee0_.LAST_NAME as LAST_NA13_1_, 
employee0_.MOBILE_NUMBER as MOBILE_14_1_, 
employee0_.PASSWORD as PASSWOR15_1_, 
employee0_.PHONE_NUMBER as PHONE_N16_1_, 
employee0_.SALARY as SALARY17_1_, 
employee0_.SALARY_TIMEFRAME as SALARY_18_1_, 
employee0_.SEX as SEX19_1_, 
employee0_.USERNAME as USERNAM20_1_, 
employee0_.WORK_LAT1 as WORK_LA21_1_, 
employee0_.WORK_LAT2 as WORK_LA22_1_, 
employee0_.WORK_LAT3 as WORK_LA23_1_, 
employee0_.WORK_LAT4 as WORK_LA24_1_, 
employee0_.WORK_LAT5 as WORK_LA25_1_, 
employee0_.WORK_LONG1 as WORK_LO26_1_, 
employee0_.WORK_LONG2 as WORK_LO27_1_, 
employee0_.WORK_LONG3 as WORK_LO28_1_, 
employee0_.WORK_LONG4 as WORK_LO29_1_, 
employee0_.WORK_LONG5 as WORK_LO30_1_ 
11:36:53,974 INFO [stdout] (default task-2)  from 
employee employee0_ 
11:36:53,974 INFO [stdout] (default task-2)  where 
employee0_.FIRST_NAME like ? 
or employee0_.LAST_NAME like ? 
or employee0_.PASSWORD like ? 
or employee0_.EMAIL_ADDRESS like ? 
or employee0_.PHONE_NUMBER like ? 
or employee0_.MOBILE_NUMBER like ? 
or employee0_.JOB_TITLE like ? 
or employee0_.JOB_DESCRIPTION like ? 
or employee0_.USERNAME like ? 
or employee0_.JOB_DETAILS like ? 

Answer 1

試試這個：

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder(); 
CriteriaQuery<T> criteriaQuery = criteriaBuilder.createQuery(typeParameterClass); 

// from 
Root<T> from = criteriaQuery.from(typeParameterClass); 
criteriaQuery.select(from); 

// like 
if (searchQuery != null && searchQuery.trim().length() > 0) { 
    List<Predicate> predicates = new ArrayList<Predicate>(); 
    for (String name : getColumnNames(typeParameterClass)) { 
    //comparing same case name 
     Predicate condition = criteriaBuilder.like(criteriaBuilder.upper(from.<String>get(name)), "%" + searchQuery.toUpperCase() + "%"); 
     predicates.add(condition); 
    } 

    //criteriaQuery.where(criteriaBuilder.or(predicates.toArray(new Predicate[] {}))); 

    Predicate[] predicatesArr = new Predicate[predicates.size()]; 
    predicates.toArray(predicatesArr); 
    query.where(predicatesArr); 
} 

List<T> results = (List<T>) entityManager.createQuery(criteriaQuery).setFirstResult(firstResult) 
     .setMaxResults(maxResults).getResultList(); 
return results; 

明智的做法是在搜索始終使用相同的情況下。