如何將ScriptA中的值傳遞給ScriptB中的類？

Question

如何通過包含類文件將值傳遞到我的類中，並將它用作該類中的$var在PHP5中？

到目前爲止的代碼：

// ScriptA 

    $cacheF=test; 

    include("ScriptB_MyClass.php"); 

    $one = new MyClass(array('$cacheF')); 
    ------------ 

    // ScripB_MyClass.php 

    class MyClass { 

     var $cacheF; 

     function __construct() { 
      $this->cacheF = $cacheF; 
      return $this->cacheF = $cacheF; 
     } 

     $the_cache_path="/home/$cacheF/myfile.txt"; 

     // execute other functions 

    } 

Answer 1

之前，我建議你仔細閱讀http://php.net/manual/en/language.oop5.php。

然而，從這裏開始......

// Something.php 
<?php 

require "MyClass.php"; 

$cacheFolder = "test"; 

$one = new MyClass($cacheFolder); 
$one->doSomething(); 


// MyClass.php 
<?php 

class MyClass { 

    protected $_cacheFolder; 
    protected $_cachePath; 

    public function __construct($_folder) { 
     $this->_cacheFolder = $_folder; 
     $this->_cachePath = '/home/' . $this->_cacheFolder . '/myfile.txt'; 
    } 

    public function doSomething() { 
     print $this->_cacheFolder . PHP_EOL . $this->_cachePath; 
    } 
}