只有項目數量呈現到購物車

Question

我試圖呈現特定項目的數據。起初我使用了一個代碼來渲染它的數量和ID。那麼它的工作。

下面的代碼：

<?php 
//render the cart for the user to view 
$cartOutput = ""; 
if(!isset($_SESSION["cart_array"]) || count($_SESSION["cart_array"]) < 1) { 
    $cartOutput = "<h2 align='center'>Your shopping cart is empty</h2>"; 
    }else{ 
     $i = 0; 
     foreach($_SESSION["cart_array"] as $each_item) { 
      $i++; 
      $item_id = $each_item['item_id']; 
      $sql = mysql_query("SELECT * FROM products WHERE id='$item_id' LIMIT 1"); 
      while($row = mysql_fetch_array($sql)){ 
       $product_name = $row["product_name"]; 
       $price = $row["price"]; 

      } 
      $cartOutput .= "<h2>Cart Item $i</h2>"; 


      while(list($key, $value) = each($each_item)) { 
       $cartOutput .= "$key: $value<br>"; 
       } 
      } 
     } 
?> 

但是當我嘗試做出更具體的像只渲染它的編號，名稱，價格和數量。它只能渲染其數量。

這就是：

<?php 
//render the cart for the user to view 
$cartOutput = ""; 
if(!isset($_SESSION["cart_array"]) || count($_SESSION["cart_array"]) < 1) { 
    $cartOutput = "<h2 align='center'>Your shopping cart is empty</h2>"; 
    }else{ 
     $i = 0; 
     foreach($_SESSION["cart_array"] as $each_item) { 
      $i++; 
      $item_id = $each_item['item_id']; 
      $sql = mysql_query("SELECT * FROM products WHERE id='$item_id' LIMIT 1"); 
      while($row = mysql_fetch_array($sql)){ 
       $product_name = $row["product_name"]; 
       $price = $row["price"]; 

      } 
      $cartOutput .= "<h2>Cart Item $i</h2>"; 
      $cartOutput .= "Item ID : " .$each_item['item_id'] . "<br>"; 
      $cartOutput .= "Item Quantity : " .$each_item['quantity'] . "<br>"; 
      $cartOutput .= "Item Name : " .$product_name . "<br>"; 
      $cartOutput .= "Item Price : Php. " .$price . "<br>"; 


      } 
     } 
?> 

有人能指導我在這裏？提前致謝。

Answer 1

我的猜測是，查詢失敗或您使用的字段名稱是錯誤的。嘗試添加這段代碼來檢查兩種可能性。

$sql = mysql_query("SELECT * FROM products WHERE id='$item_id' LIMIT 1"); 

if ($sql === false) { 
    echo 'Query Failed: ' . mysql_error(); 
} 

while($row = mysql_fetch_array($sql)) { 
    print_r($row); // check the field names in this array 

    $product_name = $row["product_name"]; 
    $price = $row["price"]; 

} 

附加SUGGESTION

試試這個，我剛纔看到輸出代碼不是while循環中。並不是說你實際上需要一個while循環，因爲你限制查詢只返回一個結果LIMIT 1。

<?php 
//render the cart for the user to view 
$cartOutput = ""; 
if(!isset($_SESSION["cart_array"]) || count($_SESSION["cart_array"]) < 1) { 
    $cartOutput = "<h2 align='center'>Your shopping cart is empty</h2>"; 
}else{ 
    $i = 0; 
    foreach($_SESSION["cart_array"] as $each_item) { 
     $i++; 
     $item_id = $each_item['item_id']; 
     $sql = mysql_query("SELECT * FROM products WHERE id='$item_id' LIMIT 1"); 
     while($row = mysql_fetch_array($sql)){ 
      // no real point in moving these values to another variable 
      // just to print them 
      //$product_name = $row["product_name"]; 
      //$price = $row["price"]; 

      $cartOutput .= "<h2>Cart Item $i</h2>"; 
      $cartOutput .= "Item ID : " . $each_item['item_id'] . "<br>"; 
      $cartOutput .= "Item Quantity : " .$each_item['quantity'] . "<br>"; 
      $cartOutput .= "Item Name : " . $row["product_name"] . "<br>"; 
      $cartOutput .= "Item Price : Php. " . $row["price"] . "<br>"; 
     }  
    } 
} 
?>