在GridView中使用圖像選擇器時膨脹類選擇器時出錯

Question

我正在使用GridView和圖像選擇器，以便在按下按鈕時與未按下按鈕時圖像不同。一切都在編譯，但是當我運行應用程序時，出現錯誤「Binary XML file line＃9：Error inflate class selector」。

是否可以在gridview中使用圖像選擇器？當我將選擇器從xml中取出時，它運行良好。

下面是每個網格項目的xml：

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
android:layout_width="wrap_content" 
android:layout_height="wrap_content" 
android:padding="5dp" > 
<selector 
    xmlns:android="http://schemas.android.com/apk/res/android"> 
    <item android:drawable="@drawable/status_button_down" 
      android:state_pressed="true" /> 
    <item android:drawable="@drawable/status_button_down" 
      android:state_focused="true" /> 
    <item android:drawable="@drawable/status_button_up" /> 
</selector> 
<TextView 
    android:id="@+id/grid_item_label" 

     android:layout_width="wrap_content" 
     android:layout_height="wrap_content" 
     android:text="Status"  
     android:textSize="9pt" 
     android:typeface="sans" 
     android:textColor="#000000" 
     android:gravity="center_horizontal" 
     android:layout_gravity="center_horizontal|bottom" 

     /> 
</LinearLayout> 

下面是該適配器爲網格視圖代碼：

public class ImageAdapter extends BaseAdapter { 
private Context mContext; 

public ImageAdapter(Context c) { 
    mContext = c; 
} 

public int getCount() { 
    //return mThumbIds.length; 
    return 16; 
} 

public Object getItem(int position) { 
    return null; 
} 

public long getItemId(int position) { 
    return 0; 
} 

// create a new ImageView for each item referenced by the Adapter 
public View getView(int position, View convertView, ViewGroup parent) { 

    LayoutInflater inflater = (LayoutInflater) mContext 
      .getSystemService(Context.LAYOUT_INFLATER_SERVICE); 

     View gridView; 
     //ImageView imageView; 
    if (convertView == null) { // if it's not recycled, initialize some attributes 

     gridView = new View(mContext); 

     // get layout from mobile.xml 
     gridView = inflater.inflate(R.drawable.status_button, null); 

     // set value into textview 
     TextView textView = (TextView) gridView 
       .findViewById(R.id.grid_item_label); 

     textView.setText("Status"); 


    } else { 
     //imageView = (ImageView) convertView; 
     gridView = (View) convertView; 

    } 

    return gridView; 

} 


} 

Answer 1

的選擇其實應該在你的「可繪」文件夾被設置爲它自己的.xml文件。那麼你可以這樣稱呼它：

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
android:background="@drawable/my_selector" 
android:layout_width="wrap_content" 
android:layout_height="wrap_content" 
android:padding="5dp" >