2012-01-12 101 views
2

我是Yii的新手。我正在爲用戶進行更改密碼頁面。當我得到驗證時,我遇到了麻煩。Yii自定義驗證和服務器端驗證?

這是視圖

<div class="form"> 
<?php $form=$this->beginWidget('CActiveForm', array(
    'id'=>'changepassword-form', 
    'enableClientValidation'=>true, 
    'clientOptions'=>array(
    'validateOnSubmit'=>true, 
    ), 
)); ?> 

<p class="note">Fields with <span class="required">*</span> are required.</p> 
<?php echo $form->errorSummary($model); ?> 
<div class="row"> 
    <?php echo $form->labelEx($model,'old_pwd'); ?> 
    <?php echo $form->textField($model,'old_pwd'); ?> 
    <?php echo $form->error($model,'old_pwd'); ?> 
</div> 

<div class="row"> 
    <?php echo $form->labelEx($model,'pwd'); ?> 
    <?php echo $form->textField($model,'pwd'); ?> 
    <?php echo $form->error($model,'pwd'); ?> 
</div> 

<div class="row"> 
    <?php echo $form->labelEx($model,'pwd_repeat'); ?> 
    <?php echo $form->passwordField($model, 'pwd_repeat'); ?> 
    <?php echo $form->error($model,'pwd_repeat'); ?> 
    <p class="hint"> 
     Passwords must be minimum 6 characters and can contain alphabets, numbers and special characters. 
    </p> 
</div> 


<div class="row buttons"> 
    <?php echo CHtml::submitButton('Change Password'); ?> 
</div> 

<?php $this->endWidget(); ?> 
</div><!-- form --> 

型號

/** 
* @return array validation rules for model attributes. 
*/ 
public function rules() 
{ 
    // NOTE: you should only define rules for those attributes that 
    // will receive user inputs. 
    return array(
     array('user, pwd, status, old_pwd, pwd_repeat', 'required'), 
     array('user', 'length', 'max'=>50), 
     array('pwd', 'length', 'max'=>30), 
     array('status', 'length', 'max'=>10), 
     array('pwd','compare'), 
     array('old_pwd','checkOldPassword'), 
     // The following rule is used by search(). 
     // Please remove those attributes that should not be searched. 
     array('id, user, pwd, status', 'safe', 'on'=>'search'), 
    ); 
} 

// FOR CHECKING IF THE PASSWORD IS VALID 
public function checkOldPassword($attribute,$params) 
{ 
    $record=Admin::model()->findByAttributes(array('pwd'=>$this->attribute)); 

    if($record===null){ 
     $this->addError($attribute, 'Invalid password'); 
    } 
} 

控制器

/** 
* Change Password for users 
*/ 
public function actionChangePassword() 
{ 
    // renders the view file 'protected/views/site/index.php' 
    // using the default layout 'protected/views/layouts/main.php' 
    if(Yii::app()->user->isGuest){ 
     // If the user is guest or not logged in redirect to the login form 
     $this->redirect(array('site/login')); 
    } 
    else{ 
     $model = new Admin; 
     if(isset($_POST['Admin'])){ 

      $model->attributes=$_POST['Admin']; 

      $this->render('changepassword',array('model'=>$model)); 
     } 
     else{ 
      $this->render('changepassword',array('model'=>$model)); 
     } 
    } 
} 

我使用自定義驗證器'checkOldPassword'用於檢查用戶的當前密碼。現在的問題是,自定義驗證不起作用。此外,如果我關閉javascript 我發現服務器端驗證錯誤也不顯示。 Iam是Yii的新人。所以請原諒任何愚蠢的錯誤。 請幫忙。

+1

「不工作「究竟如何? – Jon 2012-01-12 15:08:41

+0

@Jon自定義驗證器不顯示任何錯誤。另外,當我在瀏覽器中禁用Javascript時,它不會顯示任何驗證錯誤,即使除了自定義驗證之外的驗證規則也不會顯示。 – ajaybc 2012-01-12 15:19:43

回答

2
public function rules() 
{ 
    // NOTE: you should only define rules for those attributes that 
    // will receive user inputs. 
    public $pwd_repeat; 
    public $old_pwd; 

    return array(
    array('old_pwd,pwd_repeat,pwd','safe'), 
     array('user, pwd, status, old_pwd, pwd_repeat', 'required'), 
     array('user', 'length', 'max'=>50), 
     array('pwd', 'length', 'max'=>30), 
     array('status', 'length', 'max'=>10), 
     array('pwd','compare'), 
     array('old_pwd','checkOldPassword'), 
     // The following rule is used by search(). 
     // Please remove those attributes that should not be searched. 
     array('id, user, pwd, status', 'safe', 'on'=>'search'), 
    ); 
} 

// FOR CHECKING IF THE PASSWORD IS VALID 
public function checkOldPassword($attribute,$params) 
{ 
    $record=Admin::model()->findByAttributes(array('pwd'=>$this->attributes['old_pwd'])); 

    if($record===null){ 
     $this->addError($attribute, 'Invalid password'); 
    } 
} 

public function actionChangePassword() 
{ 
    // renders the view file 'protected/views/site/index.php' 
    // using the default layout 'protected/views/layouts/main.php' 
    if(Yii::app()->user->isGuest){ 
     // If the user is guest or not logged in redirect to the login form 
     $this->redirect(array('site/login')); 
    } 
    else{ 
     $model = new Admin; 
     if(isset($_POST['Admin'])){ 

      $model->attributes=$_POST['Admin']; 
      $model->save(); 
      $this->render('changepassword',array('model'=>$model)); 
     } 
     else{ 
      $this->render('changepassword',array('model'=>$model)); 
     } 
    } 
} 

雖仍您的計算策略是不好的...... 但是首先讓它工作..

+0

我寫你的方法不好bcz你正在檢查它的任何用戶有輸入的密碼,如果你是重置相同的...而是你應該做的是首先獲得登錄用戶的密碼如果它與用戶的輸入相同,則重置它..您可以使用$ this - > $ attribute或$ this-> attributes ['old_pwd']或$ this-> old_pwd – 2012-01-12 17:42:51

+0

謝謝你指針。但事情是,這是一個簡單的後端系統,只有一個管理員用戶。這就是爲什麼我檢查密碼是否存在於數據庫而不是用戶名。 – ajaybc 2012-01-13 06:15:11

0

試試這個:

// FOR CHECKING IF THE PASSWORD IS VALID 
public function checkOldPassword($attribute,$params) 
{ 
    $record=Admin::model()->findByAttributes(array('pwd'=>$this->pwd)); 

    if($record===null){ 
     $this->addError($attribute, 'Invalid password'); 
    } 
} 

更換$這個 - >屬性$這個 - > PWD

+0

謝謝,但沒有奏效。 – ajaybc 2012-01-12 15:09:29

+0

我也試過以下。即使這樣也行不通。我認爲別的是嚴重錯誤的。 '公共函數checkOldPassword($屬性,$ params){ $ this-> addError($ attribute,'無效的密碼'); }' – ajaybc 2012-01-12 15:11:25

0

首先我相信clientValidation將不起作用,因爲您正在檢查舊密碼,因此您需要服務器端驗證(Ajax驗證)。 clientValidation便於檢查密碼長度等

所以就把這條線: 「enableAjaxValidation」 =>真實,

其次,我會更改您的代碼是這樣的:

public function checkOldPassword($attribute,$params) 
{ 
    $record = $this->find(array(
       'select' => 'old_password', 
       'condition' => 'username=:username', 
       'params' => array(':username' => $username//or user or w/e ur gonna find user), 
        )); 

if($record===null){ 
    $this->addError($attribute, 'Invalid password'); 
} 
else { 

if($this->old_password != $record->old_password) { 

$this->addError('old_password', "Invalid Password"); 
} 
} 
}