我環顧四周,無法找到我的問題的答案。 我想從數據庫中的一行,但它只是給了我一個公告稱:注意:從數據庫請求數據時錯誤地將數組轉換爲字符串轉換
聲明:Array對/ XAMPP字符串轉換/ ...
這裏是我的代碼:
$sql6 = mysql_query("SELECT * FROM replies WHERE thread_id = $thread_id");
$numRows = mysql_num_rows($sql6);
$replies = '';
if ($numRows < 1) {
$replies = "There are no replies yet, you can make the first!";
} else {
while ($rows = mysql_fetch_array($sql6)) {
$reply_content = $rows[5];
$reply_username = $rows[7];
$reply_date = $rows[8];
$reply_author_id = [4];
$sql9 = mysql_query("SELECT * FROM users WHERE id = $reply_author_id");
$numRows = mysql_num_rows($sql);
if ($numRows < 1) {
while ($rows = mysql_fetch_array($sql)) {
$reply_user_fn = $rows['first_name'];
$reply_user_ln = $rows['last_name'];
$reply_user_id = $rows['id'];
$reply_user_pp = $rows['profile_pic'];
$reply_user_lvl = $rows['user_level'];
$reply_user_threads = $rows['threads'];
$reply_user_email = $rows['email'];
}
}
}
}
請幫幫我。我對PHP相當陌生,而且我沒有看到我做錯了什麼。
哪行數不錯誤是指什麼? –
是這行是一個錯字? '$ reply_author_id = [4];'? – Konsole