php不返​​回數據來查詢ajax函數

Question

我有和ajax函數在我的頁面加載數據從它發佈到的PHP。唯一的問題是數據不會從php頁面返回。請看一看，並告訴我在代碼中是否有任何錯誤。任何幫助非常感謝。而且這一切都應該沒有令人耳目一新。

$('#filterByPrice button', '#filterByPrice button').click(function(e){ 
    e.preventDefault(); 
    var form = $(this).closest('form'); 
    $.ajax({ 
     url: 'filter-data.php' , 
     type: 'POST', 
     data: form.serialize(), 
     success: function(data){ 
      $('.container').html(""); 
      $('.container').html(data); 
     } 
    }); 


}); 

而且PHP文件是：

<?php 

if(isset($_POST['filter'])){ 

    $searchStr = $_SESSION['searchString']; 
    $filter = $_POST['filter']; 
    if(!is_array($filter)){ 
     require_once('Connections/conn.php'); 

     $stmt = $conn->prepare("SELECT * FROM happyhours 
     WHERE (city LIKE :keyword OR zipcode LIKE :keyword) 
     AND cost = '$filter'"); 
    } 
    else { 
     $filter = implode(', ', $_POST['filter']); 
     require_once('Connections/conn.php'); 

     $stmt = $conn->prepare("SELECT * FROM happyhours 
     WHERE (city LIKE :keyword OR zipcode LIKE :keyword) 
     AND dayOfTheWeek LIKE '$filter'"); 
    } 

      try{ 
       $stmt->execute(array(':keyword' => $searchStr.'%')); 
       } 
      catch(PDOException $ex){ 
       echo $ex->getMessage(); 
       } 
     $count = $stmt->rowCount(); 
     $each = $stmt->fetch(PDO::FETCH_ASSOC); 

     if ($count > 0){ 

     do { 

     echo '<table id="results" width="700px" border="0"> 
     <tr> 
     <td rowspan="5" width="130" id="photo"><a class="lightbox" href="'.$each['imageURL'].'"><p>'.$each['name'].'</p><img id="hh-image" src="'.$each['imageURL'].'" width="80" height="80" /></a></td> 

     <tr><td id="hh-name" style="word-wrap:break-word; font-size:16px; font-family:\'Myriad Pro\'; font-weight:500" width="560" height="20"><'.$each['name'].'</td></tr> 

     <tr><td> <a href="'.$each['googleMap'].'" target="new" style="font-size:14px">'.$each['address'].'</a></td> 
     </tr> 
     <tr> 
     <td style="word-wrap:break-word; font-size:14px; font-family:\'Myriad Pro\'" height="20">'.$each['phone'].'</td> 
     </tr> 
     <tr> 
     <td style="word-wrap:break-word; font-size:14px; font-family:\'Myriad Pro\'" height="20">'.$each['dayOfTheWeek'].'&nbsp;&nbsp;('.$each['hours'].')</td> 
     </tr> 
    </table>'; 
} while($each = $stmt->fetch(PDO::FETCH_ASSOC)); 

} 

} 

?> 

Answer 1

你不能在同一:keyword佔位符多次重複的查詢時，你必須給他們不同的名字。

if(!is_array($filter)){ 
    require_once('Connections/conn.php'); 

    $stmt = $conn->prepare("SELECT * FROM happyhours 
    WHERE (city LIKE :city OR zipcode LIKE :zip) 
    AND cost = :filter"); 
} 
else { 
    $filter = implode(', ', $_POST['filter']); 
    require_once('Connections/conn.php'); 

    $stmt = $conn->prepare("SELECT * FROM happyhours 
    WHERE (city LIKE :city OR zipcode LIKE :zip) 
    AND dayOfTheWeek LIKE :filter"); 
} 

try{ 
    $stmt->execute(array(':city' => $searchStr.'%', 
         ':zip' => $searchStr.'%', 
         ':filter' => $filter)); 
} 
catch(PDOException $ex){ 
    echo $ex->getMessage(); 
}