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extern "C" int RTinet_lookup(const char * host,RTinet_address *address,RTinet_port port)
{
struct addrinfo,*res;
int errcode;
char addrstr[INET6_ADDRSTRLEN];
memset (&hints, 0, sizeof (hints));
hints.ai_family = AF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_protocol = IPPROTO_TCP;
hints.ai_flags |= AI_CANONNAME;
errcode = getaddrinfo (host, NULL , &hints, &res);
if (errcode != 0)
{
INFO("getaddrinfo");
return -1;
}
INFO(STR("Host: %s", host));
if(res == NULL)
{
INFO(STR("NULL VALUE OF RES"));
}
else
{INFO(STR("IN ELSE PART"));
while (res)
{
INFO(STR("Inside while condition with res "));
switch (res->ai_family)
{
case AF_INET:
inet_ntop(AF_INET, &((struct sockaddr_in *) res->ai_addr)->sin_addr,addrstr, INET_ADDRSTRLEN);
break;
case AF_INET6:
inet_ntop(AF_INET6, &((struct sockaddr_in6 *) res->ai_addr)->sin6_addr ,addrstr, INET6_ADDRSTRLEN);
break;
}
res = res->ai_next;
}
}
INFO(STR("IPv%d address: %s ", res->ai_family == AF_INET6 ? 6 : 4, addrstr));
return 1;
}
在這裏我通過"::1"
作爲主機地址,這是一個IPV6形式。但在跟蹤我越來越沒有得到想要的輸出
Host: ::1
IPv4 address: ::1
爲什麼這是採取IPv4?它應該採取的IPv6的地址族應AF_INET6
在這種情況下
@ Steve-o ...你能否提出爲什麼它指向null以及如何糾正它,以便獲得所需的輸出。謝謝 – 2011-05-13 05:05:48
@ Steve-o ...但是因爲我保留了一個條件,如果res == NULL,那麼INFO(STR(「NULL VALUE OF RES」)); 應該打印出來,但是這條語句不會出現在日誌中。那麼你對此有什麼建議?謝謝 – 2011-05-13 05:15:51
@Kundan,你在'res'上有一個'while'循環,直到它是'NULL',然後你試着讀'res-> ai_family'。 – 2011-05-13 12:51:50