隱祕int整型數組

Question

所以我很新的編程。我正在介紹java類，我正在嘗試提交我的項目，但是，我收到錯誤「int不能轉換爲int []」。該程序編譯好，它的工作原理，但它提交給我的網絡貓。它不能引用它。

import java.util.*; 
    /** 
    * Guess the 3 digit code and this program will tell you how many 
    * digits you have right and once you guess the correct code, 
    * it'll tell you how many guesses it took you. 
    * Press 0 to exit the program. 
    * 
    * @author (philtsoi) 
    * @version (10/05/2017) 
    */ 
    public class CodeCracker 
    { 
     /** 
     * calls the play method 
     * 
     */ 
public static void main(String []args) 
{ 
    play(); 
} 
/** 
* starts the game 
*/ 
public static void play() 
{ 
    System.out.println("Guess my 3-digit code?"); 
    Scanner in = new Scanner(System.in); 

    Random random = new Random(); 
    int correctd = random.nextInt(900) + 100; // random 3-digit code 

    int [] code = new int[3]; // array that holds 3 integers 
    int extract = 0; // extract is the one digit of guess 
    int input= 0; // input is the digits the player types in 
    int counter = 0; // counter is the number of guesses 
    int correct = counter; // correct is the digits correct 

    extract = correctd/100; 
    code[0] = extract; // first digit 
    correctd = correctd - extract * 100; 
    extract = correctd/10; 
    code[1] = extract; // second digit 
    correctd = correctd - extract * 10; 
    code[2] = correctd; // third digit 

    while (true) 
    { 
     System.out.println("Your guess? "); 
     input = in.nextInt(); 
     counter++; 
     if (input == 0) 
     { 
      System.out.println("Ok.Maybe another time."); 
      break; 
     } 
     else 
     { 
      correct = checkGuess(code, input); 
      System.out.println(input + " - " + correct + " digits correct"); 
      if (correct == 3) 
      { 
       System.out.println("You got it in " + counter + " times"); 
       break; 
      } 
     } 
    } 
} 

/** 
* This method checkGuess goes through the code and calculates each 
* digit and returns the number of correct ones 
* 
* @param code[] the array that the number being guesses is stored in 
* @param guess the integer of the next guessed digit 
* @return number of correct digits 
*/ 
public static int checkGuess(int code[], int guess) 
{ 
    int count = 0; // count is the number of digits correct 
    int extract = guess/100; // extract is the one digit of guess 
    if (code[0] == extract) 
    { 
     count++; 
     guess -= extract * 100; 
     extract = guess/10; 
    } 
    if (code[1] == extract) 
    { 
     count++; 
     guess -= extract * 10; 
    } 
    if (code[2] == guess) 
    {  
     count++; 
    } 
    return count; 
    } 

    } 

我知道一個事實，即錯誤的問題是checkGuess方法。任何幫助，將不勝感激。

這是我得到 Errors

Answer 1

這種方法checkGuess(int code[], int guess)期待一個數組，然後一個int參數的錯誤，你就不能稱之爲合格2個整數..

類測試代碼是一個失敗，你定義的變量代碼爲int[]

Answer 2

我認爲你不需要使用數組。所以，只是註釋掉你不用的東西，然後用修正！

//  int[] code = new int[3]; // array that holds 3 integers 
//  int extract = 0; // extract is the one digit of guess 
     int input = 0; // input is the digits the player types in 
     int counter = 0; // counter is the number of guesses 
     int correct = counter; // correct is the digits correct 

//  extract = correctd/100; 
//  code[0] = extract; // first digit 
//  correctd = correctd - extract * 100; 
//  extract = correctd/10; 
//  code[1] = extract; // second digit 
//  correctd = correctd - extract * 10; 
//  code[2] = correctd; // third digit 

如果你只是使用數字而不是數組，它應該像這樣完成。

public static int checkGuess(int code, int guess) { 
    int count = 0; // count is the number of digits correct 
    while(code != 0 && guess != 0){ 
     if(code % 10 == guess % 10){ 
      count++; 
     } 
     code /= 10; 
     guess /= 10; 
    } 
    return count; 
} 

此外，不要忘記調用方法，使用correctd，而不是數組。

... 
     } else { 
      correct = checkGuess(correctd, input); 
      System.out.println(input + " - " + correct + " digits correct"); 
...