1
感興趣的數據生成圖表是mymeanDT
使用mapply使用列名作爲參數
DT <- data.table(yearmonth = as.yearmon(sample(seq(as.Date('2012/07/01'), as.Date('2016/02/28'),by="day"), 5000, replace = TRUE)),
mydummy = as.factor(rbinom(5000, 1, .4)), X = runif(5000, 0, 1), Y = rnorm(5000, 20, 5), Z = runif(5000, 4, 6))
mymeanDT <- DT[, lapply(.SD, function(x) mean(x, na.rm = TRUE)), by = .(mydummy, yearmonth), .SDcols = c("X", "Y", "Z")]
我需要繪製行所有列,通過yearmonth
和mydummy
。我能做到這與以下
mycolnames <- c("X", "Y", "Z")
my_lapply_plots <- lapply(mymeanDT[, mycolnames, with = FALSE],function(mycol)
ggplot(mymeanDT, aes(x = yearmonth,y = mycol)) +
geom_line(aes(linetype = mydummy, color = mydummy)) + scale_x_yearmon() + xlab("") + ylab("") +
theme(plot.title = element_text(size = 14, hjust = -0.03)) +
scale_linetype_manual(values=c("longdash", "solid"), breaks=c(0,1),labels=c("N", "Y")) +
scale_color_manual(values=c("#701B45", "#007FAE"), breaks=c(0,1),labels=c("N", "Y")) +
ggtitle(paste("Some", "title", sep = " "))
)
我想在標題中使用的列名。所以,我想通過一個類似的功能,通過mapply
my_mapply_plots <- mapply(function(mycol, mynames)
ggplot(mymeanDT, aes(x = yearmonth,y = mycol)) +
geom_line(aes(linetype = mydummy, color = mydummy)) + scale_x_yearmon()
+ xlab("") + ylab("") +
theme(plot.title = element_text(size = 14, hjust = -0.03)) +
scale_linetype_manual(values=c("longdash", "solid"), breaks=c(0, 1),
labels=c("N", "Y")) +
scale_color_manual(values=c("#701B45", "#007FAE"), breaks=c(0, 1),
labels=c("N", "Y")) +
ggtitle(paste("Some", mycolnames, sep = " ")),
mycol = mymeanDT[, mycolnames, with = FALSE], mynames = mycolnames)
但這是輸出我得到
my_mapply_plots
X Y Z data List,5 List,5 List,5 layers List,1 List,1 List,1 scales ? ? ? mapping List,2 List,2 List,2 theme List,1 List,1 List,1 coordinates ? ? ? facet ? ? ? plot_env ? ? ? labels List,6 List,6 List,6
任何幫助,將不勝感激