拆分和合並兩個不同的字符串

Question

我想創建一個字符串，下面是我想實現的東西：我想創建最終的字符串這樣

String first = "Previous.value1 | Previous.value2"; 
String second = "New.value1| New.value2"; 

：

string final ="generate Previous.value1 cross New.value1 ? Previous.value1 cross New.value2"; 

但問題是，當我將有不匹配象下面這樣：

String first = "Previous.value1 | Previous.value2"; 
String second = "New.value1"; 

然後我想有這樣的，因爲我沒有匹配值Previous.Value2在第二個變量：

string final ="generate Previous.value1 cross New.value1"; 

到目前爲止，我成功我在最後生成字符串時，我在的價值相同的計數這兩個字符串。

string final = "generate"; 
if (first.Split('|').Count() - second.Split('|').Count() == 0) 
{ 
    int i = 0; 
    foreach (var item in first.Split('|').Count()) 
    { 
     if (i == 0) 
      final = final + item + " cross " + second.Split('|')[i]; 
     else 
      final = final + " ? " + item + " cross " + second.Split('|')[index]; 
     i++; 
    } 
} 

Answer 1

試試這個LINQ查詢（使用the Zip extension method）：

var zippedQry = first.Split('|').Zip(second.Split('|'), 
    (f, s) => f.Trim() + " cross " + s.Trim()); 
string final = "generate " + String.Join(" ? ", zippedQry.ToArray()); 

Answer 2

留在你使用的風格，我會建議先拆兩個字符串

String first = "Previous.value1 | Previous.value2"; 
String second = "New.value1 | New.value2"; 
string final = "generate "; 

string[] first_values = first.Split('|'); 
string[] second_values = second.Split('|'); 

然後你就可以只需定位在最短的陣列上即可。如果你在爲first_values的不夠的對應值有你只收集相應的。使用普通的for循環：

// run until the length of the shortest one 
for (int i = 0; i < Math.Min(first_values.Length, second_values.Length); i++) 
{ 
    // bild the normal cross-version for the first position 
    string sentence = first_values[i] + " cross " + second_values[i]; 
    // if on first position use normal version otherwise put a ? infront of it 
    final += i == 0 ? sentence : " ? " + sentence; 
} 

這個循環也應該處理的字符串是這樣的：

String first = "Previous.value1 | Previous.value2 | Previous.value3 | Previous.value4"; 
String second = "New.value1 | New.value2 | New.value3";