Play Framework：解析服務器的響應，因爲Xml返回null文檔

Question

我有一個Play網絡應用程序向服務器發出HTTP請求。

請求進行得很順利：我收到一個200狀態碼和Content-type =「application/xml」的響應。

如果我打印stdout響應正文，我看到一個格式良好的Xml文檔。

但是，如果我嘗試使用WSResponse.asXml（）從響應 創建org.w3c.dom.XML文檔，該方法返回一個空文檔。

這是我的代碼的相關部分：

private WSResponse sendPostRequest(String url, String body) { 

    WSRequest request = WS.url(url); 

    request.setHeader("Content-type", "application/x-www-form-urlencoded"); 

    return request.post(body).get(5000L); 
} 

和：

public Result requestDefaultImport() { 

    String url = "some_url"; 
    String body = "some_body"; 

    WSResponse response = sendPostRequest(url, body); 

    System.out.println(response.getBody()); //prints well-formed Xml 

    Document xmld = response.asXml(); 
    System.out.println(xmld); //prints: #[null document] 


    return ok(); 
} 

我在做什麼錯？

Answer 1

至於我可以看到你在

System.out.println(response.getBody());

打印字符串但是，你在

System.out.println(xmld); 

解決方案打印org.w3c.dom.Document中，以轉換一個文件到字符串可以在

How do I convert a org.w3c.dom.Document object to a String?

Answer 2

試試這個代碼：

Document doc = request().body().asXml(); 
Source source = new DOMSource(doc); 
StringWriter stringWriter = new StringWriter(); 
StreamResult result = new StreamResult(stringWriter); 
TransformerFactory factory = TransformerFactory.newInstance(); 
javax.xml.transform.Transformer transformer = factory.newTransformer(); 
transformer.transform(source, result); 
String xmlStr = stringWriter.getBuffer().toString(); 
System.out.println(xmlStr); 

或者這一點，如果從SOAP消耗：

Document doc = soapBody.extractContentAsDocument(); 
Source source = new DOMSource(doc); 
StringWriter stringWriter = new StringWriter(); 
Result result = new StreamResult(stringWriter); 
TransformerFactory factory = TransformerFactory.newInstance(); 
Transformer transformer = factory.newTransformer(); 
transformer.transform(source, result); 
strSoapBody = stringWriter.getBuffer().toString();