刪除功能不起作用？

Question

我想知道爲什麼這段代碼不起作用？該按鈕執行正確的確認序列，但該記錄實際上並未被刪除。我複製並粘貼了工作按鈕中的代碼，並且我認爲在轉移中我錯過了指定詳細信息的情況？

if (isset($_GET['deleteseries'])) { 
    echo 'Do you really want to delete ' 
     . $_GET['series'] 
     . '? <a href="editstock.php?yesdelete=' 
     . $_GET['id'] 
     . '">Yes</a> | <a href="editstock.php">No</a>'; 
    exit(); 
} 

if (isset($_GET['yesdelete'])) { 
    $deleteSQL = sprintf("DELETE FROM series WHERE id='%s' LIMIT 1", 
     GetSQLValueString($_GET['yesdelete'], "int")); 

    mysql_select_db($database_connectmysql, $connectmysql); 
    $Result1 = mysql_query($deleteSQL, $connectmysql) or die(mysql_error()); 
    header("location: editstock.php"); 
    exit(); 
} 

使用此按鈕：

<input name="deleteseries" 
    type="button" id="deleteseries" 
    value="delete" 
    style="width:20%; float:right" 
    onclick="window.location.href = '?deleteseries=delete&id=<?php echo $row_seriesrecordset['id']; ?>&series=<?php echo $row_seriesrecordset['series']; ?>'"/> 

Answer 1

試試這個：

if (isset($_GET['yesdelete'])) { 
    $deleteSQL = sprintf("DELETE FROM series WHERE id='%s' LIMIT 1", 
     GetSQLValueString($_GET['yesdelete'], "int")); 

    mysql_select_db($database_connectmysql, $connectmysql); 
    $Result1 = mysql_query($deleteSQL, $connectmysql) or die(mysql_error()); 
    echo "deleted entry with ID ".$_GET['yesdelete']; 
    exit; 
    header("location: editstock.php"); 
    exit(); 
} 

它說什麼入口被刪除？也許你通過錯誤的「yesdelete」參數（錯誤的ID）..

Answer 2

一切都是正確的，只是你在下面的代碼犯了個小錯誤：

if (isset($_GET['yesdelete'])) { 
    $deleteSQL = sprintf("DELETE FROM series WHERE id='. $_GET['yesdelete'] LIMIT 1", 
     GetSQLValueString($_GET['yesdelete'], "int")); 

    mysql_select_db($database_connectmysql, $connectmysql); 
    $Result1 = mysql_query($deleteSQL, $connectmysql) or die(mysql_error()); 
    header("location: editstock.php"); 
    exit(); 
}