0
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
txtUserName=(EditText)this.findViewById(R.id.txtUname);
txtPassword=(EditText)this.findViewById(R.id.txtPwd);
btnLogin=(Button)this.findViewById(R.id.btnLogin);
Button btnLogin=(Button)this.findViewById(R.id.Button01);
btnLogin.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if((txtUserName.getText().toString()).equals(txtPassword.getText().toString())){
Toast.makeText(LoginappActivity.this, "Login Successful",Toast.LENGTH_LONG).show();
}
else
{
Toast.makeText(LoginappActivity.this, "Invalid Login",Toast.LENGTH_LONG).show();
}
}
}
);
Button next = (Button) findViewById(R.id.Button01);
next.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Intent myIntent = new Intent(view.getContext(), AddName.class);
startActivityForResult(myIntent, 0);
}});
}
}
當應用程序在模擬器中運行時,它已成功編譯,但我不知道是否有成功的登錄或無效登錄。我無法看到應用程序是否成功登錄
@Abhinai你接受的答案與我的答案有什麼區別?我的回答是在其他答案之前發佈的,但仍選擇該答案! – Antrromet
我只能選擇一個答案,因此在點擊上述答案時切換 – Abhinai