我有我的應用程序的一部分,這個實施後:無法從視圖去另一個做一些說明
爲什麼當我點擊「CERCA每ISBN」按鈕,它進入的tableView沒有做我寫的說明?
這是「CERCA每ISBN」按鈕的代碼,我點擊:
@IBAction func ISBNButtonClick(_ sender: Any) {
let libro = Libro.text! as String
if Libro.text!.isEmpty {
//Alert per segnalare i campi mancanti, oltre a caselle rosse
var myAlert = UIAlertController(title:"Attenzione\n", message:"Inserire il codice ISBN", preferredStyle:UIAlertControllerStyle.alert);
let okAction = UIAlertAction(title:"Ok", style:UIAlertActionStyle.default){ action in }
myAlert.addAction(okAction);
self.present(myAlert, animated:true, completion:nil);
// placeholder rosso se la text è vuota
Libro.attributedPlaceholder = NSAttributedString(string:"Digita qui...", attributes: [NSForegroundColorAttributeName: UIColor.red])
//se tutti i campi obbligatori sono stati inseriti, proseguo ad altri controlli
}else{
if(isNumeric(string: libro)){
if((libro.characters.count) < 13 || (libro.characters.count) > 13){
//Alert per segnalare l'ISBN più corto di 13 numeri
var myAlert = UIAlertController(title:"Attenzione\n", message:"L'ISBN deve essere di 13 cifre", preferredStyle:UIAlertControllerStyle.alert);
let okAction = UIAlertAction(title:"Ok", style:UIAlertActionStyle.default){ action in }
myAlert.addAction(okAction);
self.present(myAlert, animated:true, completion:nil);
}else{
//inviare dati al server
let myUrl = NSURL(string:"http://chuadiv.ddns.net/easytoschool/fetch_book_detailed.php");
let request = NSMutableURLRequest(url:myUrl as! URL);
request.httpMethod = "POST";
let postString = "name=\(libro)&mail=\(UserDefaults.standard.object(forKey: "userEmail") as? String)";
request.httpBody = postString.data(using: String.Encoding.utf8);
let task = URLSession.shared.dataTask(with: request as URLRequest){
data, response, error in
if error != nil{
print("error=\(error)")
return
}
var err: NSError?
do{
var json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSArray
if let parseJSON: NSArray = json{
for index in 0...parseJSON.count-1 {
print("ciao")
let libro = parseJSON[index] as! [String:Any]
print("\n\n",index,":\n")
let book = resultCell.init(bookId: libro["id"] as! String,bookName: libro["name"] as! String,bookAuthor: libro["author"] as! String,bookSchool: libro["school"] as! String,bookPrice: libro["price"] as! String,bookStatus: libro["status"] as! String,bookISBN: libro["isbn"] as! String,bookType: libro["type"] as! String,bookIdSeller: libro["idSeller"] as! String,bookNameSeller: libro["nameSeller"] as! String,bookSurnameSeller: libro["surnameSeller"] as! String)
book.printBook();
HomeViewController.booksArray.append(book)
}
}
}catch{
print("error=\(error)")
return
}
}
task.resume();
performSegue(withIdentifier: "homeToListBook", sender: self)
}
}else{
var myAlert = UIAlertController(title:"Attenzione\n", message:"Inserire solo numeri per la ricerca attraverso codice ISBN", preferredStyle:UIAlertControllerStyle.alert);
let okAction = UIAlertAction(title:"Ok", style:UIAlertActionStyle.default){ action in }
myAlert.addAction(okAction);
self.present(myAlert, animated:true, completion:nil);
}
}
}
我想,當我按下按鈕,設置我的數組並把它轉到的tableView後,但我可以「T
我寫了你的代碼部分,但它不起作用。它會立即轉到另一個視圖而不打印「if part」 – Marco
在另一個視圖中,我想先打印數組,但它告訴「索引超出範圍」;我認爲這是因爲它立即進入視圖沒有設置數組 – Marco
而我在我的應用的另一部分有這種錯誤 – Marco