異步equivilent到array.some（）中的NodeJS

Question

我需要遍歷集合檢查是否存在每一個在我的數據庫

一排是有。有的（）異步等效異步真實的彙總結果/對整個集合進行虛假檢查？

Answer 1

可以使用async模塊，具體這種方法async.eachhttps://github.com/caolan/async#each

https://www.npmjs.com/package/async這裏的故宮包

增加了一個小例子（而不是我的if你想在你的數據庫檢查）

var tests = ['a', 'b']; 
async.each(tests, function(test, callback) { 

    if(test === 'c') { 
    return callback('We cannot have a c') 
    } 

    return callback(); 
}, function(err){ 
    // if any of the file processing produced an error, err would equal that error 
    if(err) { 
     // One of the iterations produced an error. 
     // All processing will now stop. 
     console.log('C was found'); 
    } else { 
     console.log('All Tests are ok'); 
    } 
});