如何使用數組顯示數據庫中的所有數據

Question

我試圖將$countries連接到一個數組，該數組將顯示我的數據庫中的所有數據，它只顯示我輸入的最後一個數據。無論如何我都可以顯示他們全部？

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 

$sql = "SELECT product_id, product_name , quantity FROM inventory"; 
$result = $conn->query($sql); 

if ($result->num_rows > 0) { 
    // output data of each row 
    while($row = $result->fetch_assoc()) { 
     $tom = array(" ". $row["quantity"] . $row["product_name"]); 
     $countries = $tom; 
    } 
} else { 
    echo "0 results"; 
} 

$conn->close(); 

Answer 1

，因爲你已經assinged數據$國家錯誤的方式：

$countries = array(); 
if ($result->num_rows > 0) { 
    // output data of each row 
    while($row = $result->fetch_assoc()) { 
     $tom = array(" ". $row["quantity"] . $row["product_name"]); 
     $countries[] = $tom; // use [] 
    } 
} else { 
    echo "0 results"; 
} 

Answer 2

$countries[] = $tom; 

用[]以可變的inicialization結束時，您將行添加到陣列。如果你在沒有[]的情況下這樣做，這只是在while循環中每次都是官方化的。

Answer 3

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 

$sql = "SELECT product_id, product_name , quantity FROM inventory"; 
$result = $conn->query($sql); 

if ($result->num_rows > 0) { 
    // output data of each row 
    while($row = $result->fetch_assoc())   
     $countries[] = " ". $row["quantity"] . $row["product_name"];  
} else { 
    echo "0 results"; 
} 

$conn->close(); 

Answer 4

// create connection 
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); 
$conn = new mysqli($servername, $username, $password, $dbname); 

// get the data 
$sql = "SELECT product_id, product_name, quantity FROM inventory"; 
$countries = $conn->query($sql)->fetch_all(); 

雖然這只是available with mysqlnd installations，你需要一個，因爲沒有mysqlnd mysqli的是不可用的反正。