LEFT JOIN兩個表具有相同的列名，並用PHP

Question

打印出來，我有兩個表我的MySQL數據庫：

USERS ('id_user' - 'id_client' -> the same as the id in CLIENTS) 
CLIENTS ('id_client' - 'name' etc.) 

我想打印所有的客戶和各個用戶。這是我的查詢：

SELECT * FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client 

這似乎是確定的，但我有麻煩時，我嘗試從表clients打印的id_client。我如何使用PHP打印它們？看起來他們是空的......我的查詢是否錯誤？

Answer 1

嘗試，

無論GROUP BY或DISTINCT需要

SELECT * FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client GROUP BY c.id_client 

Answer 2

比

簡單，只要做到以下幾點：

SELECT c.*, u.name FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client 

這將選擇一切從表C的，只有名字來自表u。你遇到的問題是你從兩個表中選擇id_client，這是不必要的，並且在嘗試使用php引用時會引起混淆。

Answer 3

SELECT c。 ，u。 FROM clients c LEFT outer JOIN users u ON c.id_client = u.id_client

Answer 4

由於您在兩個表（「id_client」）中都有相同名稱的字段，所以您必須指定要打印哪一個。

像這樣：

SELECT u.id_client, c.id_client, ... FROM clients AS c LEFT JOIN users AS u ON c.id_client = u.id_client