需要將以下字符串對象前一個號碼下結合

Question

a=[1,'hi','what',2,'how','where',3,'one',4,'two','three','four',5,'five','six'] 

或

a = ["1",'hi','what',"2",'how','where',"3",'one',"4",'two','thre‌​e','four',"5",'five'‌​,'six'] 

我需要創建哈希的陣列狀

a=[{1=>['hi','what']},{2=>['how','where']},{3=>['one']},{4=>['two','three','four']},{5=>['five','six']}] 

我可以使用任何預定義的功能來實現這一？

Answer 1

你可以使用slice_before：

a = [1,'hi','what',2,'how','where',3,'one',4,'two','three','four',5,'five','six'] 

p a.slice_before(Integer).map{ |int, *words| { int => words } } 
#=> [{1=>["hi", "what"]}, {2=>["how", "where"]}, {3=>["one"]}, {4=>["two", "three", "four"]}, {5=>["five", "six"]}] 

注意，對於不同的鍵散列的陣列可以在一個單一的哈希凝結：

a.slice_before(Integer).map{ |int, *words| [int, words] }.to_h 
#=> {1=>["hi", "what"], 2=>["how", "where"], 3=>["one"], 4=>["two", "three", "four"], 5=>["five", "six"]} 

更新：

如果你的密鑰串看起來像一個數字，你可以嘗試：

a = ["1",'hi','what',"2",'how','where',"3",'one',"4",'two','three','four',"5",'five','six'] 
a.slice_before(/^\-?\d+$/).map{ |int, *words| [int.to_i, words] }.to_h 
#=> {1=>["hi", "what"], 2=>["how", "where"], 3=>["one"], 4=>["two", "three", "four"], 5=>["five", "six"]}