我一直在尋找通過互聯網,我還沒有找到任何類似的線程。 問題是我一直使用filter_input(INPUT_SERVER, "REQUEST_METHOD");
來獲取表單是否已經提交,但是今天我開發了一個登錄系統,在使用PHP時奇怪的行爲,在這裏你有我的代碼實際使用:檢查提交的表單(方法POST)不起作用
$email = filter_input(INPUT_POST, "email");
$pass = filter_input(INPUT_POST, "pass");
print "done0";
if(filter_input(INPUT_SERVER, "REQUEST_METHOD") != "POST") {
return;
}
print "done1";
if(!isset($email) || !isset($pass)) {
return;
}
print "done2";
和HTML之一:
<form action="#" method="POST" accept-charset="UTF-8" autocomplete="off" class="col s12">
<div class="row">
<div id="login-panel">
<div class="col s12">
<h2 class="white-text center-align">System sign-in</h2>
</div>
<div class="input-field col s12">
<i class="material-icons prefix white-text">email</i>
<input type="email" name="email" class="validate white-text" autofocus required>
<label for="email" id="email-label"
data-error="You must provide a correct email (example: [email protected])">Your email</label>
</div>
<div class="input-field col s12">
<i class="material-icons prefix white-text">visibility_off</i>
<input type="password" name="password" class="validate white-text" required>
<label for="pass">Your password</label>
</div>
<div class="input-field col s12">
<button class="btn waves-effect waves-light" id="login-button" type="submit" name="action">Submit
<i class="material-icons right">send</i>
</button>
</div>
</div>
</div>
</form>
最後,我使用了兌現API和的JQuery 2.1.1
希望有人能幫助我,謝謝!
與此代碼會發生什麼? – chris85