Bash有什麼用$＃

Question

我對Bash腳本很陌生，有人能向我解釋$＃和$嗎？在下面的代碼中工作？

#!/bin/bash 

ARGS=3   # Script requires 3 arguments. 
E_BADARGS=85 # Wrong number of arguments passed to script. 

if [ $# -ne "$ARGS" ] 
then 
    echo "Usage: `basename $0` old-pattern new-pattern filename" 
    exit $E_BADARGS 
fi 

old_pattern=$1 
new_pattern=$2 

if [ -f "$3" ] 
then 
    file_name=$3 
else 
    echo "File \"$3\" does not exist." 
    exit $E_BADARGS 
fi 

exit $? 

Answer 1

從Learn Bash in Y minutes：

# Builtin variables: 
# There are some useful builtin variables, like 
echo "Last program's return value: $?" 
echo "Script's PID: $$" 
echo "Number of arguments passed to script: $#" 
echo "All arguments passed to script: $@" 
echo "Script's arguments separated into different variables: $1 $2..." 

Answer 2

從https://www.gnu.org/software/bash/manual/html_node/Special-Parameters.html

$#擴展爲十進制位置參數的數目。

$?擴展到最近執行的前臺管道的退出狀態。

Answer 3

$#顯示的腳本參數 $?的數字顯示最後一個腳本的返回值

有關參數：echo "ARG[$#]"之前if，然後執行類似

腳本

script.sh 1 

的輸出中會

ARG[1] 
Usage: g old-pattern new-pattern filename 

等

的$?的輸出中也可以用於在命令行上：

#shell>ls 
file1.txt  g    inpu    nodes_list 
#shell>echo $? 
0 

#shell>ls FileNameNotFound 
ls: FileNameNotFound: No such file or directory 
#shell> echo $? 
1